一、函数重载
函数重载是一种特殊情况,C++允许在同一作用域中声明几个类似的同名函数,这些同名函数的形参列表(参数个数,类型,顺序)必须不同。
注意:c语言不允许函数重载
下面同名set,但是不同的形参列表,执行不同的任务。
#include "iostream" using namespace std; class Person{ public: void set(int num,string name){ this->number=num; this->name=name; cout<<"name: "<< this->name; cout<<" number: "<< this->number<<endl; } void set(string name){ this->name=name; cout<<"name: "<< this->name<<endl; } private: string name; int number; }; int main(){ Person person; person.set(133,"antonio");//name: antonio number: 133 person.set("steve");//name: steve return 0; }
二、运算符重载
运算符重载是让运算符在不同情况执行不同功能。
重载运算符格式
返回值类型 operator 运算符名称 (形参表列){ //TODO: }
具体示例如下:
#include "iostream" using namespace std; class Complex{ public: //默认构造函数 Complex(){ this->real=0.0; this->imaginary=0.0; } Complex(float real,float imaginary){ this->real=real; this->imaginary=imaginary; } void setReal(float real){ this->real=real; } void setImaginary(float imaginary){ this->imaginary=imaginary; } void show(){ cout<<"imaginary number is :"<<this->real<<"+"<<this->imaginary<<"i"<<endl; } //重载运算符+ Complex operator +(const Complex &a){ Complex B; B.real=this->real+a.real; B.imaginary=this->imaginary+a.imaginary; return B; } //const修饰形参表明是一个输入参数,在函数内部不可以改变其值 friend Complex operator -(const Complex &a,const Complex &b); private: float real; float imaginary; }; //重载-为全局函数,故而需要在类中设置友元 Complex operator -(const Complex &a,const Complex &b){ Complex B; B.real=a.real-b.real; B.imaginary=a.imaginary-b.imaginary; return B; } int main(){ Complex complex1(10.5,10.7); Complex complex2(10.2,10.5); Complex complex3=complex1+complex2; Complex complex4=complex1-complex2; complex1.show();//imaginary number is :10.3+10.4i complex2.show();//imaginary number is :10.5+10.6i complex3.show();//imaginary number is :20.8+21i complex4.show();//imaginary number is :0.3+0.2i return 0; }