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  • P2172 [国家集训队]部落战争 二分图最小不相交路径覆盖

    二分图最小不相交路径覆盖

    #include<bits/stdc++.h>
    using namespace std;
    const int MAXN = 5550;
    const int MAXM = 1000005;
    const int INF = 1000000050;
    int Head[MAXN], cur[MAXN], lev[MAXN], to[MAXM << 1], nxt[MAXM << 1], f[MAXM << 1], ed = 1, S, T;
    inline void addedge(int u, int v, int cap)
    {
        to[++ed] = v;
        nxt[ed] = Head[u];
        Head[u] = ed;
        f[ed] = cap;
        to[++ed] = u;
        nxt[ed] = Head[v];
        Head[v] = ed;
        f[ed] = 0;
        return;
    }
    inline bool BFS()
    {
        int u;
        memset(lev, -1, sizeof(lev));
        queue<int>q;
        lev[S] = 0;
        q.push(S);
        while (q.size()) {
            u = q.front();
            q.pop();
            for (int i = Head[u]; i; i = nxt[i])
                if (f[i] && lev[to[i]] == -1) {
                    lev[to[i]] = lev[u] + 1;
                    q.push(to[i]);
                    /*
                    if (to[i] == T)
                    {
                            return 1;
                    }
                    magic one way optimize
                    */
                }
        }
        memcpy(cur, Head, sizeof Head);
        return lev[T] != -1;
    }
    inline int DFS(int u, int maxf)
    {
        if (u == T || !maxf) {
            return maxf;
        }
        int cnt = 0;
        for (int &i = cur[u], tem; i; i = nxt[i])
            if (f[i] && lev[to[i]] == lev[u] + 1) {
                tem = DFS(to[i], min(maxf, f[i]));
                maxf -= tem;
                f[i] -= tem;
                f[i ^ 1] += tem;
                cnt += tem;
                if (!maxf) {
                    break;
                }
            }
        if (!cnt) {
            lev[u] = -1;
        }
        return cnt;
    }
    int Dinic()
    {
        int ans = 0;
        while (BFS()) {
            ans += DFS(S, 2147483647);
        }
        return ans;
    }
    void init(int SS, int TT)
    {
        memset(Head, 0, sizeof(Head));
        ed = 1;
        S = SS;
        T = TT;
        return;
    }
    char ff[205][205];
    int dir[5][2];
    int aim[205][205];
    int cnt = 0;
    int main()
    {
        int n, m;
        int r, c;
        int u, v;
        scanf("%d %d %d %d", &n, &m, &r, &c);
        dir[1][0] = dir[2][1] = r;
        dir[1][1] = dir[2][0] = c;
        dir[3][0] = c, dir[4][0] = r;
        dir[3][1] = -r, dir[4][1] = -c;
        if(r==c)
        {
            dir[2][0]=dir[2][1]=dir[4][0]=dir[4][1]=50;
        }
        for (int i = 1; i <= n; i++) {
            scanf("%s", ff[i]+1);
        }
        for (int i = 1; i <= n; i++) {
            for (int j = 1; j <= m; j++) {
                if (ff[i][j] == '.') {
                    aim[i][j] = ++cnt;
                }
            }
        }
        S = 0, T = 2 * cnt + 1;
        for (int i = 1; i <= cnt; i++) {
            addedge(S, i, 1);
            addedge(cnt + i, T, 1);
        }
        for (int i = 1; i <= n; i++)
            for (int j = 1; j <= m; j++) {
                if (ff[i][j] == '.') {
                    for (int k = 1; k <= 4; k++) {
                        int dx = i + dir[k][0];
                        int dy = j + dir[k][1];
                        if (dx >= 1 && dx <= n && dy >= 1 && dy <= m) {
                            if (ff[dx][dy] == '.') {
                                u = aim[i][j], v = aim[dx][dy] + cnt;
                                addedge(u, v, 1);
                                //cout<<i<<" "<<j<<" "<<dx<<" "<<dy<<endl;
                            }
                        }
                    }
                }
            }
        cout << cnt - Dinic() << endl;
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/Aragaki/p/10694881.html
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