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  • Leetcode-5175 Can Make Palindrome from Substring(构建回文串检测)

     1 #define _for(i,a,b) for(int i = (a);i < b;i ++)
     2 #define _rep(i,a,b) for(int i = (a);i > b;i --)
     3 
     4 class Solution
     5 {
     6     public:
     7         vector<bool> canMakePaliQueries(string s, vector<vector<int>>& queries)
     8         {
     9             vector<bool> v;
    10             long long sum[100003][27];
    11             memset(sum,0,sizeof(sum));
    12             sum[1][s[0]-'a'] ++;
    13             _for(i,2,s.size()+1)
    14             {
    15                 memcpy(sum[i],sum[i-1],sizeof(sum[i]));
    16                 sum[i][s[i-1]-'a'] ++;
    17             }
    18             
    19             _for(i,0,queries.size())
    20             {
    21                 int rnt = 0;
    22                 _for(j,0,27)
    23                 {
    24                     int tmp = sum[queries[i][1]+1][j]-sum[queries[i][0]][j];
    25                     if(tmp&0x1)
    26                         rnt ++;
    27                 }
    28                 if(rnt/2<=queries[i][2])
    29                     v.push_back(true);
    30                 else
    31                     v.push_back(false);
    32             }
    33             return v;
    34         }
    35 };
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  • 原文地址:https://www.cnblogs.com/Asurudo/p/11442044.html
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