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  • [LeetCode] Convert Sorted Array to Binary Search Tree

    Given an array where elements are sorted in ascending order, convert it to a height balanced BST.

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      实现方法有两种,一种是二叉树自下往上 实现,一种是自上往下实现。我用的是后一种方法。
     
    #include <iostream>
    #include <vector>
    using namespace std;
    /**
     * Definition for binary tree
     */
    struct TreeNode {
        int val;
        TreeNode *left;
        TreeNode *right;
        TreeNode(int x) : val(x), left(NULL), right(NULL) {}
    };
    
    class Solution {
    public:
        TreeNode *sortedArrayToBST(vector<int> &num) {
            int n = num.size();
            if(n ==0)   return NULL;
            if(n==1)    return new TreeNode(num[0]);
            return helpFun(num,0,n-1);
        }
    
        TreeNode * helpFun(vector<int> &num,int lft,int rgt)
        {
            if(lft>rgt) return NULL;
            if(lft==rgt)    return new TreeNode(num[lft]);
            int mid = (lft+rgt)/2;
            TreeNode * curNode = new TreeNode(num[mid]);
            curNode->left = helpFun(num,lft,mid-1);
            curNode->right = helpFun(num,mid+1,rgt);
            return curNode;
        }
    };
    
    int main()
    {
    
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/Azhu/p/4335674.html
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