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  • noip刷题记录 20170818

    天天爱跑步

    lca + 树上差分

    #include<iostream>
    #include<cstdio>
    #include<cstdlib>
    #include<cstring>
    #include<string>
    #include<cmath>
    #include<algorithm>
    #include<vector>
    using namespace std;
    
    const int N = 3e5 + 5, M = 3e5 + 5;
    int n, m, ans[N], offset;
    int ecnt, adj[N], go[M << 1], nxt[M << 1];
    int w[N], dep[N], cnt[N << 2], fa[N][25];
    struct node{
        int val, delta;
        node(){}
        node(int a, int b):val(a), delta(b){}
    }; 
    vector<node> tag[N];
    
    inline void addEdge(int u, int v){
        nxt[++ecnt] = adj[u], adj[u] = ecnt, go[ecnt] = v;
        nxt[++ecnt] = adj[v], adj[v] = ecnt, go[ecnt] = u;
    }
    
    inline int getLca(int u, int v){
        if(dep[u] < dep[v]) swap(u, v);
        int delta = dep[u] - dep[v];
        for(int i = 20; i >= 0; i--)
            if((1 << i) & delta) u = fa[u][i];
        if(u == v) return u;
        for(int i = 20; i >= 0; i--)
            if(fa[u][i] != fa[v][i]) 
                u = fa[u][i], v = fa[v][i];
        return fa[u][0];
    }
    
    inline void dfs(int u, int f){
        fa[u][0] = f;
        for(int i = 1; i <= 20; i++)
            fa[u][i] = fa[fa[u][i - 1]][i - 1];
        for(int e = adj[u], v; e; e = nxt[e]){
            v = go[e];
            if(v != f){
                dep[v] = dep[u] + 1;
                dfs(v, u);
            }
        }
    }
    
    inline void solve(int u){
        int cur = cnt[dep[u] + w[u]] + cnt[w[u] - dep[u] + offset];
        for(int i = 0; i < tag[u].size(); i++)
            cnt[tag[u][i].val] += tag[u][i].delta;
        for(int e = adj[u], v; e; e = nxt[e]){
            if((v = go[e]) == fa[u][0]) continue;
            solve(v);
        }
        ans[u] = cnt[dep[u] + w[u]] + cnt[w[u] - dep[u] + offset] - cur;
    }
    
    inline int read(){
        int i = 0, f = 1; char ch = getchar();
        for(; (ch < '0' || ch > '9') && ch != '-'; ch = getchar());
        if(ch == '-') f = -1, ch = getchar();
        for(; ch >= '0' && ch <= '9'; ch = getchar())
            i = (i << 3) + (i << 1) + (ch - '0');
        return i * f;
    }
    
    inline void wr(int x){
        if(x < 0) putchar('-'), x = -x;
        if(x > 9) wr(x / 10);
        putchar(x % 10 + '0');
    }
    
    int main(){
        n = read(), m = read(), offset = 3 * n + 1; 
        for(int i = 1; i < n; i++){
            int x = read(), y = read();
            addEdge(x, y);
        }
        dfs(1, 0);
        for(int i = 1; i <= n; i++) w[i] = read();
        for(int i = 1; i <= m; i++){
            int s = read(), t = read(), lca = getLca(s, t);
            tag[s].push_back(node(dep[s], 1));
            tag[t].push_back(node(dep[s] - 2 * dep[lca] + offset, 1));
            tag[fa[lca][0]].push_back(node(dep[s], -1));
            tag[lca].push_back(node(dep[s] - 2 * dep[lca] + offset, -1));
        }
        solve(1);
        for(int i = 1; i <= n; i++) wr(ans[i]), putchar(' ');
        return 0;
    }
    View Code

    借教室

    二分法

    #include<iostream>
    #include<cstdio>
    #include<cstdlib>
    #include<cstring>
    #include<string>
    #include<algorithm>
    #include<vector>
    using namespace std;
    
    const int N = 1e6 + 5;
    int n, m, a[N], f[N], s[N], t[N], d[N], ans;
    
    inline int read(){
        int i = 0, f = 1; char ch = getchar();
        for(; (ch < '0' || ch > '9') && ch != '-'; ch = getchar());
        if(ch == '-') f = -1, ch = getchar();
        for(; ch >= '0' && ch <= '9'; ch = getchar())
            i = (i << 3) + (i << 1) + (ch - '0');
        return i * f;
    }
    
    inline void wr(int x){
        if(x < 0) putchar('-'), x = -x;
        if(x > 9) wr(x / 10);
        putchar(x % 10 + '0');
    }
    
    inline bool check(int mid){
        int sum = 0;
        memset(f, 0, sizeof f);
        for(int i = 1; i <= mid; i++)
            f[s[i]] += d[i], f[t[i] + 1] -= d[i];
        for(int i = 1; i <= n; i++){
            sum += f[i];
            if(sum > a[i]) return false;
        }
        return true;
    }
    
    int main(){
        n = read(), m = read();
        for(int i = 1; i <= n; i++) a[i] = read();
        for(int i = 1; i <= m; i++) d[i] = read(), s[i] = read(), t[i] = read();
        int l = 1, r = m; 
        while(l <= r){
            int mid = l + r >> 1;
            if(check(mid)) l = mid + 1;
            else ans = mid, r = mid - 1;
        }
        if(ans == 0) putchar('0');
        else{
            wr(-1), putchar('
    ');
            wr(ans);
        }
        return 0;
    }
    View Code

    线段树

    #include<iostream>
    #include<cstdio>
    #include<cstdlib>
    #include<cstring>
    #include<string>
    #include<cmath>
    #include<algorithm>
    using namespace std;
    
    const int N = 1e6 + 5, oo = 0x3f3f3f3f;
    int n, m, minn[N * 4], a[N], tag[N * 4];
    
    inline int read(){
        int i = 0, f = 1; char ch = getchar();
        for(; (ch < '0' || ch > '9') && ch != '-'; ch = getchar());
        if(ch == '-') f = -1, ch = getchar();
        for(; ch >= '0' && ch <= '9'; ch = getchar())
            i = (i << 3) + (i << 1) + (ch - '0');
        return i * f;
    }
    
    inline void wr(int x){
        if(x < 0) putchar('-'), x = -x;
        if(x > 9) wr(x / 10);
        putchar(x % 10 + '0');
    }
    
    inline void build(int k, int l, int r){
        if(l == r){
            minn[k] = a[l];
            return;
        }
        int mid = l + r >> 1, lc = k << 1, rc = k << 1 | 1;
        build(lc, l, mid);
        build(rc, mid + 1, r);
        minn[k] = min(minn[lc], minn[rc]);
    }
    
    inline void minuss(int k, int v){
        minn[k] -= v;
        tag[k] += v;
    }
    
    inline void pushDown(int k){
        if(tag[k]){
            if(minn[k << 1] != -1) minuss(k << 1, tag[k]);
            if(minn[k << 1 | 1] != -1) minuss(k << 1 | 1, tag[k]);
            tag[k] = 0;
        }
    }
    
    
    inline void modify(int k, int l, int r, int x, int y, int v){
        if(x <= l && r <= y){
            minuss(k, v);
            return;
        }
        pushDown(k);
        int mid = l + r >> 1, lc = k << 1, rc = k << 1 | 1, ret = oo;
        if(x <= mid) modify(lc, l, mid, x, y, v);
        if(y > mid) modify(rc, mid + 1, r, x, y, v);
        minn[k] = min(minn[lc], minn[rc]);
    }
    
    inline int query(int k, int l, int r, int x, int y){
        if(x <= l && r <= y) return minn[k];
        pushDown(k);
        int mid = l + r >> 1, lc = k << 1, rc = k << 1 | 1, ret = oo;
        if(x <= mid) ret = min(ret, query(lc, l, mid, x, y));
        if(y > mid) ret = min(ret, query(rc, mid + 1, r, x, y));
        return ret;
    }
    
    int main(){
        n = read(), m = read();
        for(int i = 1; i <= n; i++) a[i] = read();
        memset(minn, -1, sizeof tag);
        build(1, 1, n); 
        for(int i = 1; i <= m; i++){
            int d = read(), s = read(), t = read();
            if(s > t) swap(s, t);
    //        cout<<s<<" "<<t<<" "<<query(1, 1, n, s, t)<<"!!!"<<endl;
            if(query(1, 1, n, s, t) < d){
                wr(-1), putchar('
    '), wr(i);
                return 0;
            }
            modify(1, 1, n, s, t, d);
        }
        wr(0);
        return 0;
    }
    View Code

    积木大赛

    简单分析

    #include<iostream>
    #include<cstdio>
    #include<cstdlib>
    #include<cstring>
    #include<string>
    #include<algorithm>
    #include<cmath>
    using namespace std;
    
    const int N = 1e5 + 5;
    int n, ans, last;
    
    int main(){
        cin >> n;
        for(int i = 1; i <= n; i++){
            int tmp; cin >> tmp;
            if(tmp - last > 0) ans += tmp - last;
            last = tmp;
        }
        cout << ans;
        return 0;
    }
    View Code

    Vigenère密码

    简单分析 + 模拟

    #include<iostream>
    #include<cstdio>
    #include<cstdlib>
    #include<cstring>
    #include<string>
    #include<algorithm>
    #include<cmath>
    using namespace std;
    
    int klen, slen, key[1005];
    char k[1005], s[1005], t[1005];
    
    int main(){
        cin >> k >> s;
        klen = strlen(k), slen = strlen(s);
        for(int i = 0; i < klen; i++){
            if('a' <= k[i] && k[i] <= 'z')
                key[i] = k[i] - 'a';
            else key[i] = k[i] - 'A'; 
        }
        for(int i = 0; i < slen; i++){
            if('a' <= s[i] && s[i] <= 'z'){
                t[i] = s[i] - key[i % (klen)];
                while(t[i] < 'a') t[i] += 26;
            }
            else if('A' <= s[i] && s[i] <= 'Z'){
                t[i] = s[i] - key[i % (klen)];
                while(t[i] < 'A') t[i] += 26;
            }
            else continue;
            putchar(t[i]);
        }
        return 0;
    }
    View Code

    花匠

    动态规划 + 树状数组优化

    #include<iostream>
    #include<cstdio>
    #include<cstdlib>
    #include<cstring>
    #include<string>
    #include<algorithm>
    #include<cmath>
    using namespace std;
    
    const int N = 1e5 + 5, H = 1e6 + 5;
    int n, h[N], f[N], g[N], maxh, maxxF[H], maxxG[H], ans;
    
    inline int read(){
        int i = 0, f = 1; char ch = getchar();
        for(; (ch < '0' || ch > '9') && ch != '-'; ch = getchar());
        if(ch == '-') f = -1, ch = getchar();
        for(; ch >= '0' && ch <= '9'; ch = getchar())
            i = (i << 3) + (i << 1) + (ch - '0');
        return i * f;
    }
    
    inline void wr(int x){
        if(x < 0) putchar('-'), x = -x;
        if(x > 9) wr(x / 10);
        putchar(x % 10 + '0');
    }
    
    inline void uptF(int x, int v){
        for(int i = x; i <= maxh; i += (i&(-i)))
            maxxF[i] = max(maxxF[i], v);
    }
    
    inline void uptG(int x, int v){
        for(int i = x; i <= maxh; i += (i&(-i)))
            maxxG[i] = max(maxxG[i], v);
    }
    
    inline int queryF(int x){
        int ret = 0;
        for(int i = x; i > 0; i-=(i&-i))
            ret = max(maxxF[i], ret);
        return ret;
    }
    
    inline int queryG(int x){
        int ret = 0;
        for(int i = x; i > 0; i-=(i&-i))
            ret = max(ret, maxxG[i]);
        return ret;
    }
    
    int main(){
        n = read();
        for(int i = 1; i <= n; i++) h[i] = read() + 1, maxh = max(maxh, h[i]);
        maxh += 5;
        for(int i = 1; i <= n; i++){
            f[i] = max(queryG(h[i] - 1) + 1, f[i]);
            g[i] = max(queryF(maxh - h[i] - 1) + 1, g[i]);
            uptF(maxh - h[i], f[i]);
            uptG(h[i], g[i]);
            ans = max(ans, max(f[i], g[i]));
        }
        wr(ans);
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/CzYoL/p/7391153.html
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