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  • 【HDU1325】Is It A Tree?(并查集基础题)

    有以下坑点:

    1.结束输入不一定-1,题目中的叙述只是说所有权值都为正值。

    2.是否构成一棵树不能只判断是否只有一个根节点,没有环路,而且还需要判断每个节点的入度一定是1,不然就不是一棵树。

    (无环路也可用树的性质:结点数 = 边树 + 1 来取代)

     1 #include <iostream>
     2 #include <cstdlib>
     3 #include <cstring>
     4 #include <cctype>
     5 #include <cmath>
     6 #include <string>
     7 #include <cstdio>
     8 #include <algorithm>
     9 #include <numeric>
    10 using namespace std;
    11 
    12 const int maxn = 25;
    13 
    14 int  father[maxn];
    15 int  eage[maxn];
    16 bool vis[maxn], flag = 0;
    17 int sum = 0;
    18 
    19 int getFather (int x) {
    20     while (father[x] != x) {
    21         x = father[x];
    22     }
    23     return x;
    24 }
    25 
    26 void Union (int p, int q) {
    27     int x = getFather (p);
    28     int y = getFather (q);
    29     if (x != y) {
    30         father[y] = x;
    31         sum ++;
    32     } else {
    33         flag = 0;
    34     }
    35 }
    36 
    37 int main () {
    38     int x, y, cur = 0;
    39     while (cin >> x >> y) {
    40         if (x < 0 && y < 0) break;
    41         if (x == 0 && y == 0) {
    42             printf("Case %d is a tree.
    ", ++ cur);
    43             continue;
    44         } else {
    45             flag = 1;
    46             memset(vis, 0, sizeof(vis));
    47             memset(eage, 0, sizeof(eage));
    48             for (int i = 0; i < maxn; ++ i) {
    49                 father[i] = i;
    50             }
    51             vis[x] = vis[y] = 1;
    52             Union(x, y);
    53             eage[y] ++;
    54             while (cin >> x >> y) {
    55                 if (x + y == 0) break;
    56                 vis[x] = vis[y] = 1;
    57                 Union(x, y);
    58                 eage[y] ++;
    59             }
    60             sort(eage, eage + maxn, greater<int>());
    61             int xx = 0;
    62             if (eage[0] > 1) flag = 0;
    63             for (int i = 1; i < maxn; ++ i) {
    64                 if (vis[i] && father[i] == i) {
    65                     xx ++;
    66                     if (xx > 1) {flag = 0; break;}
    67                 }
    68             }
    69             /*for (int i = 1 ; i < maxn; ++ i) {
    70                 cout << vis[i] <<  " " ;
    71             }*/
    72 
    73             if (flag) printf("Case %d is a tree.
    ", ++ cur);
    74             else printf("Case %d is not a tree.
    ", ++ cur);
    75         }
    76     }
    77     return 0;
    78 }
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  • 原文地址:https://www.cnblogs.com/Destiny-Gem/p/3861247.html
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