Python练习-函数版-锁定三次登陆失败的用户

代码如下:

# 编辑者：闫龙
if __name__ == '__main__':
    import UserLoginFuncation
    
LoclCount=[];
while True:
    UserName = input("用户名:>>")
    if(UserLoginFuncation.CheckUserLock(UserName)):
        print("用户",UserName,"已被锁定")
        continue
    PassWd = input("密  码:>>")
    if(UserLoginFuncation.UserInfo(UserName,PassWd)):
        print("欢迎",UserName,"登陆")
        break
    else:
        LoclCount.append(UserName);
        print("用户名或密码错误,您还有",3-LoclCount.count(UserName),"次尝试机会")
    if(LoclCount.count(UserName) == 3):
        UserLoginFuncation.LockUser(UserName)
        print("对不起,尝试次数过多",UserName,"用户已被锁定")

# 编辑者：闫龙
import os
def CheckUserLock(UserName):
    if(os.path.exists("LockUser")):
        with open("LockUser","r",encoding="utf8") as ReadLock:
            p = ReadLock.readline().split(",")
            if(p.count(UserName) != 0):
                return True

def LockUser(UserName):
    if(os.path.exists("LockUser")):
        LockFile = open("LockUser", "a", encoding="utf8")
        LockFile.write(UserName+",")
        LockFile.close()
    else:
        LockFile = open("LockUser", "w", encoding="utf8")
        LockFile.write(UserName+",")
        LockFile.close()

def UserInfo(UserName,PassWd):
    with open("UserInfo",mode="r",encoding="utf8") as userinfo:
        p =  userinfo.readlines()
        for i in p:
            i= i.strip().split(":")
            if(i[0] == UserName and i[1] == PassWd):
                return True
            else:
                continue
        return False

egon:123
alex:321
long:666