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  • MySQL练习-主外键多表查询

    练习:

    1.建立表关系:

    请创建如下表,并创建相关约束

     1 USE db1;
     2 CREATE TABLE class(
     3     cid INT AUTO_INCREMENT PRIMARY KEY,
     4     caption VARCHAR(10)
     5 );
     6 CREATE TABLE teacher(
     7     tid INT AUTO_INCREMENT PRIMARY KEY,
     8     tname VARCHAR(10)
     9 );
    10 CREATE TABLE course(
    11     cid INT AUTO_INCREMENT PRIMARY KEY,
    12     cname VARCHAR(10),
    13     teach_id INT,
    14     CONSTRAINT fk_course_teacher FOREIGN KEY(teach_id) REFERENCES teacher(tid)
    15 );
    16 CREATE TABLE student(
    17     sid INT AUTO_INCREMENT PRIMARY KEY,
    18     sname VARCHAR(10),
    19     gender VARCHAR(10),
    20     class_id INT,
    21     CONSTRAINT fk_student_class FOREIGN KEY(class_id) REFERENCES class(cid)
    22 );
    23 CREATE TABLE score(
    24     sid INT AUTO_INCREMENT PRIMARY KEY,
    25     student_id INT,
    26     course_id INT,
    27     number INT,
    28     CONSTRAINT fk_score_student FOREIGN KEY(student_id) REFERENCES student(sid),
    29     CONSTRAINT fk_score_course FOREIGN KEY(course_id) REFERENCES course(cid)
    30 );
    创建表并建立表关系
     1 INSERT INTO class(caption) VALUES("三年二班");
     2 INSERT INTO class(caption) VALUES("一年三班");
     3 INSERT INTO class(caption) VALUES("三年一班");
     4 
     5 INSERT INTO teacher(tname) VALUES("波多");
     6 INSERT INTO teacher(tname) VALUES("苍空");
     7 INSERT INTO teacher(tname) VALUES("饭岛");
     8 
     9 INSERT INTO student(sname,gender,class_id) VALUES("钢蛋","女",1);
    10 INSERT INTO student(sname,gender,class_id) VALUES("铁锤","女",1);
    11 INSERT INTO student(sname,gender,class_id) VALUES("山炮","男",2);
    12 
    13 INSERT INTO course(cname,teach_id) VALUES("生物",1);
    14 INSERT INTO course(cname,teach_id) VALUES("体育",1);
    15 INSERT INTO course(cname,teach_id) VALUES("物理",2);
    16 
    17 INSERT INTO score(student_id,course_id,number) VALUES(1,1,60);
    18 INSERT INTO score(student_id,course_id,number) VALUES(1,2,59);
    19 INSERT INTO score(student_id,course_id,number) VALUES(2,2,100);
    表数据
    1 ALTER TABLE score ADD UNIQUE sco_que(student_id,course_id);
    补充联合唯一

    2.操作练习:

    1、自行创建测试数据

    1 INSERT INTO student(sname,gender,class_id) VALUES("钢铁侠","男",4);
    2 -- Cannot add or update a child row: a foreign key constraint fails (`db1`.`student`, CONSTRAINT `fk_student_class` FOREIGN KEY (`class_id`) REFERENCES `class` (`cid`))
    测试失败数据

    2、查询“生物”课程比“物理”课程成绩高的所有学生的学号;

    1 SELECT s1.student_id FROM (SELECT a.student_id,a.`number` FROM score a,course b 
    2 WHERE a.`course_id` = b.`cid` AND b.`cname` ="生物") s1 , (SELECT a.student_id,a.`number` FROM score a,course b 
    3 WHERE a.`course_id` = b.`cid` AND b.`cname`="体育") s2
    4 WHERE s1.`student_id` = s2.student_id AND s1.number >s2.number
    多表嵌套查询

    3、查询平均成绩大于60分的同学的学号和平均成绩;

    1 SELECT student_id,AVG(number)
    2 FROM score 
    3 GROUP BY student_id
    4 HAVING AVG(number) > 60
    HAVING用法

    4、查询所有同学的学号、姓名、选课数、总成绩;

    1 SELECT a.`sid`,a.`sname`,b.`cname`,c.`number`,c.`course_id`,a.`class_id` 
    2 FROM student a,course b,score c
    3 WHERE a.`sid` = c.`student_id` AND c.`course_id` = b.`cid`
    多表查询

    5、查询姓“李”的老师的个数;

    1 SELECT count(*) as a from teacher where tname LIKE '李%'

    6、查询没学过“叶平”老师课的同学的学号、姓名;

    1 SELECT a.sid,a.sname FROM student a,teacher b,course c
    2 WHERE a.class_id = c.cid and b.tid = c.teach_id AND b.tname != '叶平'
    多表查询

    7、查询学过“001”并且也学过编号“002”课程的同学的学号、姓名;

    1 SELECT a.`student_id`,c.`sname` FROM score a , score b ,student c
    2 WHERE a.`student_id`=b.`student_id` AND a.`course_id` ='1' 
    3 AND b.`course_id`='2' AND c.`sid` = a.`student_id`
    多表查询

    8、查询学过“叶平”老师所教的所有课的同学的学号、姓名;

     1 SELECT c.`sid`,c.`sname` FROM student c 
     2 LEFT JOIN score d ON c.`sid` = d.`student_id`
     3 LEFT JOIN course b ON d.`course_id` = b.`cid`
     4 LEFT JOIN teacher a ON a.`tid` = b.`teach_id`
     5 WHERE a.`tname`='波多'
     6 GROUP BY c.`sname`
     7 HAVING COUNT(c.sname)
     8 <(SELECT COUNT(*) FROM teacher a 
     9 LEFT JOIN course b ON a.`tid` = b.`teach_id`
    10 WHERE a.`tname`='波多')
    乱七八糟一大堆

    9、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名;

    1 SELECT s1.student_id FROM (SELECT a.student_id,a.`number` FROM score a,course b 
    2 WHERE a.`course_id` = b.`cid` AND b.`cid` ='2') s1 , (SELECT a.student_id,a.`number` FROM score a,course b 
    3 WHERE a.`course_id` = b.`cid` AND b.`cid`='1') s2
    4 WHERE s1.`student_id` = s2.student_id AND s1.number >s2.number
    多表嵌套查询

    10、查询有课程成绩小于60分的同学的学号、姓名;

    1 SELECT a.`sid`,a.`sname` FROM student a , score    b
    2 WHERE a.sid = b.student_id AND number < 60

    11、查询没有学全所有课的同学的学号、姓名;

    1 SELECT a.`sid`,a.`sname` FROM student a 
    2 LEFT JOIN score b ON  a.`sid` = b.`student_id`
    3 GROUP BY a.`sid`
    4 HAVING COUNT(b.`student_id`) < (SELECT COUNT(*) FROM course)
    Having 子查询

    12、查询至少有一门课与学号为“001”的同学所学相同的同学的学号和姓名;

    1 SELECT a.`sid`,a.`sname` FROM student a LEFT JOIN score b ON a.`sid` = b.`student_id`
    2 LEFT JOIN course c ON c.`cid` = b.`course_id`
    3 WHERE c.`cid` IN (
    4 SELECT cc.`cid` FROM student aa LEFT JOIN score bb ON aa.`sid` = bb.`student_id`
    5 LEFT JOIN course cc ON cc.`cid` = bb.`course_id` WHERE aa.`sid`='1'
    6 ) AND a.`sid` !='1'
    又是乱七八糟一大堆

    13、查询至少学过学号为“001”同学所选课程中任意一门课的其他同学学号和姓名;

    SELECT a.`sid`,a.`sname` FROM student a LEFT JOIN score b ON a.`sid` = b.`student_id`
    LEFT JOIN course c ON c.`cid` = b.`course_id`
    WHERE c.`cid` IN (
    SELECT cc.`cid` FROM student aa LEFT JOIN score bb ON aa.`sid` = bb.`student_id`
    LEFT JOIN course cc ON cc.`cid` = bb.`course_id` WHERE aa.`sid`='1'
    ) AND a.`sid` !='1'
    完全一模一样啊

    14、查询和“002”号的同学学习的课程完全相同的其他同学学号和姓名;

     1 SELECT a.`sid`,a.`sname` FROM student a LEFT JOIN score b ON a.`sid` = b.`student_id`
     2 LEFT JOIN course ac ON b.`course_id`=ac.`cid`
     3 WHERE
     4  ac.`cid` IN (SELECT c.`cid` FROM student a LEFT JOIN score b ON a.`sid` = b.`student_id`
     5 LEFT JOIN course c ON b.`course_id`=c.`cid` WHERE a.`sid`='2') 
     6 AND a.`sid` != '2' 
     7 GROUP BY a.`sid`,a.`sname`
     8 HAVING
     9 (SELECT COUNT(ac.`cid`) AS countCid FROM student aa LEFT JOIN score b ON aa.`sid` = b.`student_id`
    10 LEFT JOIN course ac ON b.`course_id`=ac.`cid` WHERE aa.`sid`=a.`sid`)
    11  = (SELECT COUNT(c.`cid`) AS cc FROM student a LEFT JOIN score b ON a.`sid` = b.`student_id`
    12 LEFT JOIN course c ON b.`course_id`=c.`cid` WHERE a.`sid`='2')
    抠抠抠抠抠一下午,抠出来了

    15、删除学习“叶平”老师课的SC表记录;

    1 DELETE FROM score WHERE course_id IN (
    2 SELECT a.`cid` FROM course a LEFT JOIN teacher b ON a.`teach_id`=b.`tid`
    3 WHERE b.`tname`='叶平'
    4 )
    这个这么简单?

    16、向SC表中插入一些记录,这些记录要求符合以下条件:①没有上过编号“002”课程的同学学号;②插入“002”号课程的平均成绩;
    17、按平均成绩从低到高显示所有学生的“语文”、“数学”、“英语”三门的课程成绩,按如下形式显示: 学生ID,语文,数学,英语,有效课程数,有效平均分;
    18、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分;
    19、按各科平均成绩从低到高和及格率的百分数从高到低顺序;
    20、课程平均分从高到低显示(现实任课老师);
    21、查询各科成绩前三名的记录:(不考虑成绩并列情况)
    22、查询每门课程被选修的学生数;
    23、查询出只选修了一门课程的全部学生的学号和姓名;
    24、查询男生、女生的人数;
    25、查询姓“张”的学生名单;
    26、查询同名同姓学生名单,并统计同名人数;
    27、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列;
    28、查询平均成绩大于85的所有学生的学号、姓名和平均成绩;
    29、查询课程名称为“数学”,且分数低于60的学生姓名和分数;
    30、查询课程编号为003且课程成绩在80分以上的学生的学号和姓名;
    31、求选了课程的学生人数
    32、查询选修“杨艳”老师所授课程的学生中,成绩最高的学生姓名及其成绩;
    33、查询各个课程及相应的选修人数;
    34、查询不同课程但成绩相同的学生的学号、课程号、学生成绩;


    35、查询每门课程成绩最好的前两名;

    1 SELECT student_id FROM score 
    2 ORDER BY number DESC LIMIT 2
    这个肯定不对

    36、检索至少选修两门课程的学生学号;

    1 SELECT a.`sid` FROM student a LEFT JOIN score b ON a.`sid` = b.`student_id`
    2 GROUP BY a.`sid`
    3 HAVING COUNT(a.`sid`)>=2
    完美~

    37、查询全部学生都选修的课程的课程号和课程名;

    1 SELECT DISTINCT c.`cid`,c.`cname` FROM student a 
    2 LEFT JOIN score b ON a.`sid` = b.`student_id`
    3 LEFT JOIN course c ON b.`course_id`=c.`cid`
    应该对了

    38、查询没学过“叶平”老师讲授的任一门课程的学生姓名;

    1 SELECT a.`sname` FROM student a 
    2 LEFT JOIN score b ON a.`sid` = b.`student_id`
    3 LEFT JOIN course c ON c.`cid` = b.`course_id`
    4 WHERE c.`cid` NOT IN (
    5 SELECT cour.`cid` FROM teacher teac 
    6 LEFT JOIN course cour ON teac.`tid`=cour.`teach_id`
    7 WHERE teac.`tname` = '波多' 
    8 )
    差不多吧

    39、查询两门以上不及格课程的同学的学号及其平均成绩;

    1 SELECT student_id,COUNT(sid) AS co,AVG(number)AS avgg  FROM score 
    2 WHERE number < 60 
    3 GROUP BY student_id
    4 HAVING co >=2
    so anyway

    40、检索“004”课程分数小于60,按分数降序排列的同学学号;

    1 SELECT b.`sid`,b.`sname`,a.`number` FROM score a LEFT JOIN student b ON a.`student_id` = b.`sid`
    2 WHERE a.`course_id` = '4' AND a.`number` < '60'
    3 ORDER BY a.`number` DESC
    恩不难

    41、删除“002”同学的“001”课程的成绩;

    1 DELETE FROM score WHERE student_id ='2' AND course_id = '1'
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  • 原文地址:https://www.cnblogs.com/DragonFire/p/6949767.html
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