题目链接
https://www.patest.cn/contests/gplt/L1-044
题意
根据对方给出剪刀石头步 给出对应的胜利出招,每K次 要有一个平局
思路
用一个循环,然后每K次 判断一下
AC代码
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <deque>
#include <vector>
#include <queue>
#include <string>
#include <cstring>
#include <map>
#include <stack>
#include <set>
#include <cstdlib>
#include <ctype.h>
#include <numeric>
#include <sstream>
using namespace std;
typedef long long LL;
const double PI = 3.14159265358979323846264338327;
const double E = 2.718281828459;
const double eps = 1e-6;
const int MAXN = 0x3f3f3f3f;
const int MINN = 0xc0c0c0c0;
const int maxn = 1e5 + 5;
const int MOD = 1e9 + 7;
int main()
{
map <string, string> m;
m["ChuiZi"] = "Bu";
m["Bu"] = "JianDao";
m["JianDao"] = "ChuiZi";
int k;
cin >> k;
k ++;
string s;
for (int i = 1; ; i++)
{
cin >> s;
if (s == "End")
break;
else
{
if (i % k == 0)
cout << s << endl;
else
cout << m[s] << endl;
}
}
}