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  • MySQL 查询练习

    #课程表
    DROP TABLE IF EXISTS `course`;
    CREATE TABLE `course` (
      `CNO` char(5) NOT NULL,
      `CNAME` varchar(10) NOT NULL,
      `TNO` int(10) NOT NULL,
      PRIMARY KEY (`CNO`)
    ) ENGINE=MyISAM AUTO_INCREMENT=348 DEFAULT CHARSET=utf8;
    -- ----------------------------
    -- Table structure for score
    -- ----------------------------
    #成绩表
    DROP TABLE IF EXISTS `score`;
    CREATE TABLE `score` (
      `SNO` varchar(3) NOT NULL,
      `CNO` varchar(5) NOT NULL,
      `DEGREE` decimal(10,1) NOT NULL
    ) ENGINE=MyISAM AUTO_INCREMENT=348 DEFAULT CHARSET=utf8;
    #学生表
    -- ----------------------------
    -- Table structure for student
    -- ----------------------------
    DROP TABLE IF EXISTS `student`;
    CREATE TABLE `student` (
      `SNO` int(10) NOT NULL,
      `SNAME` varchar(4) NOT NULL,
      `SSEX` tinyint(2) NOT NULL,
      `SBIRTHDAY` datetime DEFAULT NULL,
      `CLASS` varchar(5) DEFAULT NULL,
      PRIMARY KEY (`SNO`)
    ) ENGINE=MyISAM AUTO_INCREMENT=348 DEFAULT CHARSET=utf8;
    #教师表
    -- ----------------------------
    -- Table structure for teacher
    -- ----------------------------
    DROP TABLE IF EXISTS `teacher`;
    CREATE TABLE `teacher` (
      `TNO` varchar(3) NOT NULL,
      `TNAME` varchar(4) NOT NULL,
      `TSEX` tinyint(2) NOT NULL,
      `TBIRTHDAY` datetime NOT NULL,
      `PROF` varchar(6) DEFAULT NULL,
      `DEPART` varchar(10) NOT NULL,
      PRIMARY KEY (`TNO`)
    ) ENGINE=MyISAM AUTO_INCREMENT=348 DEFAULT CHARSET=utf8;

    以课程号升序、成绩降序查询成绩表的所有记录。
    SELECT * from score ORDER BY cno asc, degree DESC;

    查询“95031”班的学生人数。
    SELECT COUNT(CLASS) as 9501班 FROM student WHERE class="95033";
    查询‘3-105’号课程的平均分
    SELECT AVG(degree) FROM score WHERE CNO="3-105";
    SELECT avg(degree) 平均分  from score GROUP BY cno HAVING cno = '3-105';
    查询成绩表中至少有5名学生选修的并以3开头的课程的平均分数。
    SELECT CNO,avg(degree) from score  GROUP BY CNO HAVING  COUNT(*)>5 and CNO like "3%";
    查询最低分大于70,最高分小于90的学生编号 列
    SELECT SNO  from score  GROUP BY SNO HAVING  min(DEGREE)>70 and MAX(DEGREE)<90;
    查询选修“3-105”课程的成绩高于“109”号同学成绩的所有同学的记录。
    SELECT  stu.* from  student stu LEFT JOIN score sc ON sc.SNO=stu.SNO and cno="3-105" and sc.DEGREE>
    (SELECT degree FROM score WHERE CNO="3-105" AND SNO=109 )

    查询score中选学一门以上课程的同学中分数为非最高分成绩的记录。
    SELECT score.* from score INNER JOIN
    (SELECT sno ,MAX(degree) as maxdegree from score GROUP BY sno HAVING COUNT(*) >1) temp
    on score.sno = temp.sno and score.degree < temp.maxdegree;

    查询和学号为107的同学同年出生的所有学生的Sno、Sname和Sbirthday列
    SELECT sno,sname,sbirthday FROM student WHERE YEAR(SBIRTHDAY)=
    (SELECT YEAR(SBIRTHDAY) from student WHERE SNO=107);

    查询“张旭“教师任课的学生成绩
    SELECT * from score WHERE cno in (SELECT cno from course WHERE tno = (SELECT tno from teacher WHERE tname ='张旭'));
    查询出“计算机系“教师所教课程的成绩表。
    SELECT * from score WHERE cno in (SELECT CNO from course WHERE TNO in (SELECT tno from teacher WHERE DEPART = '计算机系'));
    查询“计算机系”与“电子工程系“不同职称的教师的名字和职称。
    SELECT tname ,prof from teacher WHERE DEPART = '计算机系' and  prof not in (SELECT prof from teacher WHERE DEPART = '电子工程系')
    UNION
    SELECT tname ,prof from teacher WHERE DEPART = '电子工程系' and  prof not in (SELECT prof from teacher WHERE DEPART = '计算机系');
    查询所有教师和同学的名字、性别和生日.
    SELECT sname as name , ssex as sex , sbirthday as birthday from student
    UNION ALL #万一老师和学生姓名 性别 出生日相同呢 所以加了ALL
    SELECT tname , tsex  , tbirthday as birthday from teacher;


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  • 原文地址:https://www.cnblogs.com/JohnsonZilch/p/6549916.html
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