zoukankan      html  css  js  c++  java
  • C. Vanya and Scales

    time limit per test
    1 second
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output
     

    Vanya has a scales for weighing loads and weights of masses w0, w1, w2, ..., w100 grams where w is some integer not less than 2(exactly one weight of each nominal value). Vanya wonders whether he can weight an item with mass m using the given weights, if the weights can be put on both pans of the scales. Formally speaking, your task is to determine whether it is possible to place an item of mass m and some weights on the left pan of the scales, and some weights on the right pan of the scales so that the pans of the scales were in balance.

    Input

    The first line contains two integers w, m (2 ≤ w ≤ 109, 1 ≤ m ≤ 109) — the number defining the masses of the weights and the mass of the item.

    Output

    Print word 'YES' if the item can be weighted and 'NO' if it cannot.

    Examples
    input
    3 7
    output
    YES
    input
    100 99
    output
    YES
    input
    100 50
    output
    NO

    Note

    Note to the first sample test. One pan can have an item of mass 7 and a weight of mass 3, and the second pan can have two weights of masses 9 and 1, correspondingly. Then 7 + 3 = 9 + 1.

    Note to the second sample test. One pan of the scales can have an item of mass 99 and the weight of mass 1, and the second pan can have the weight of mass 100.

    Note to the third sample test. It is impossible to measure the weight of the item in the manner described in the input.

     1 #include<bits/stdc++.h>
     2 using namespace std;
     3 
     4 int main()
     5 {
     6     int a,b,c;
     7     scanf("%d%d",&a,&b);
     8     while(b)
     9     {
    10         c=b%a;
    11         if(!c)b/=a;
    12         else if(c==1){b=(b-1)/a;}
    13         else if(c==a-1){b=(b+1)/a;}
    14         else{puts("NO");return 0;}
    15     }
    16     puts("YES");
    17 }
  • 相关阅读:
    持续集成(Continuous Integration),
    python的几个有趣点
    C++语言发展历史 & 基础知识
    [C++] Windows下的socket编程(这是一个简单的TCP/IP例子)
    office app 代码简析之 task pane app
    佳言玩具
    数据的图形可视化[R语言结果GML引发出来的调查]
    收藏的一系列教程帖子,很适合有一定基础,想要进阶的同学
    各种排序算法总结
    三层架构+存储过程实现分页
  • 原文地址:https://www.cnblogs.com/Kiven5197/p/5851013.html
Copyright © 2011-2022 走看看