leetcode Reverse Bits

Reverse bits of a given 32 bits unsigned integer.

For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).

Follow up:
If this function is called many times, how would you optimize it?

Related problem: Reverse Integer

简单题，思路就是左移1位，如果左移出来的是1，那么假如原来表示的是2的2次方，reversed bits要表示的就是2的19次方（31-2）

那么循环32次，把所有的位读取完毕就好了。

ps：今天第一次8点到实验室。来一道简单的题目宽慰鼓励我吗？gogo fighting~

class Solution {
public:
    uint32_t reverseBits(uint32_t n) {
        int temp=0,result=0;
        for(int i=0;i<32;i++){
            if(n&1==1) temp=pow(2,31-i);
            else temp=0;
            result+=temp;
            n>>=1;
        }
        return result;
    }
};