Lele now is thinking about a simple function f(x). if x < 10 f(x)=x if x >= 10 f(x) = a0*f(x-1)+a1*f(x-2)+a2*f(x-3)+……+a9*f(x-10) And ai (0 <= i <= 9) can only be 0 or 1 . Now, I will give a0 ~ a9 and two positive integers k and m ,and could you help Lele to caculate f(k)%m.?
输入
The problem contains mutiple test cases.Please process to the end of file. In each case, there will be two lines. In the first line , there are two positive integers k and m. ( k < 2*1000000000,m < 10000) In the second line , there are ten integers represent a0 ~ a9.
输出
For each case, output f(k) % m in one line.
样例输入
10 9999 1 1 1 1 1 1 1 1 1 1 20 500 1 0 1 0 1 0 1 0 1 0
样例输出
45 104
#include<iostream> using namespace std; int a[10]; int f(int x) { int y; if(x<10) y=x; else y=a[0]*f(x-1)+a[1]*f(x-2)+a[2]*f(x-3)+a[3]*f(x-4)+a[4]*f(x-5)+a[5]*f(x-6)+a[6]*f(x-7)+a[7]*f(x-8)+a[8]*f(x-9)+a[9]*f(x-10); return y; } int main() { int k,m,i; while(cin>>k>>m) { for(i=0;i<10;i++) cin>>a[i]; cout<<f(k)%m<<endl; } return 0; }