zoukankan      html  css  js  c++  java
  • python——井字小游戏

    import random  
      
      
    def drawBoard(board):  
        # 打印棋盘  
      
      
        # "board"是长度为10的列表,为了方便输入,忽略第一个元素board[0]  
      
      
        print('
    
    
    
    ')  
        print('			┌--─┬--─┬--─┐')  
        print(''+board[7]+''+board[8]+''+board[9]+'')  
        print('			├--─┼--─┼─--┤')  
        print(''+board[4]+''+board[5]+''+board[6]+'')  
        print('			├--─┼--─┼─--┤')  
        print(''+board[1]+''+board[2]+''+board[3]+'')  
        print('			└--─┴--─┴─--┘')  
      
      
    def inputPlayerLetter():  
        # 让玩家选择棋子  
        # 返回一个列表,第一个是玩家的棋子,第二个是电脑的  
        letter = ''  
        while not (letter == 'X' or letter == 'O'):  
            print('Do you want to be X or O?')  
            letter = input().upper()  
      
      
        if letter == 'X':  
            return ['X', 'O']  
        else:  
            return ['O', 'X']  
      
      
    def whoGoesFirst():  
        # 随机产生谁先走  
        if random.randint(0, 1) == 0:  
            return 'computer'  
        else:  
            return 'player'  
      
      
    def playAgain():  
        # 再玩一次?输入yes或y返回True  
        print('Do you want to play again? (yes or no)')  
        return input().lower().startswith('y')  
      
      
    def makeMove(board, letter, move):  
        #落子  
        board[move] = letter  
      
      
    def isWinner(bo, le):  
        # 判断所给的棋子是否获胜  
        # 参数为棋盘上的棋子(列表)和棋子符号  
        # 以下是所有可能胜利的情况,共8种  
        return ((bo[7] == le and bo[8] == le and bo[9] == le) or   
        (bo[4] == le and bo[5] == le and bo[6] == le) or   
        (bo[1] == le and bo[2] == le and bo[3] == le) or   
        (bo[7] == le and bo[4] == le and bo[1] == le) or   
        (bo[8] == le and bo[5] == le and bo[2] == le) or   
        (bo[9] == le and bo[6] == le and bo[3] == le) or  
        (bo[7] == le and bo[5] == le and bo[3] == le) or  
        (bo[9] == le and bo[5] == le and bo[1] == le))   
      
      
    def getBoardCopy(board):  
        # 复制一份棋盘,供电脑落子时使用  
        dupeBoard = []  
      
      
        for i in board:  
            dupeBoard.append(i)  
      
      
        return dupeBoard  
      
      
    def isSpaceFree(board, move):  
        # 判断这个位置是否有子,没子返回True  
        return board[move] == ' '  
      
      
    def getPlayerMove(board):  
        # 玩家落子  
        move = ' '  
        while move not in '1 2 3 4 5 6 7 8 9'.split() or not isSpaceFree(board, int(move)):  
            print('What is your next move? (1-9)')  
            move = input()  
        return int(move)  
      
      
    def chooseRandomMoveFromList(board, movesList):  
        # 随机返回一个可以落子的坐标  
        # 如果没有所给的movesList中没有可以落子的,返回None  
        possibleMoves = []  
        for i in movesList:  
            if isSpaceFree(board, i):  
                possibleMoves.append(i)  
      
      
        if len(possibleMoves) != 0:  
            return random.choice(possibleMoves)  
        else:  
            return None  
      
      
    def getComputerMove(board, computerLetter):  
        # 确定电脑的落子位置  
        if computerLetter == 'X':  
            playerLetter = 'O'  
        else:  
            playerLetter = 'X'  
      
      
        # Tic Tac Toe AI核心算法:  
        # 首先判断电脑方能否通过一次落子直接获得游戏胜利  
        for i in range(1, 10):  
            copy = getBoardCopy(board)  
            if isSpaceFree(copy, i):  
                makeMove(copy, computerLetter, i)  
                if isWinner(copy, computerLetter):  
                    return i  
      
      
        # 判断玩家下一次落子能否获得胜利,如果能,给它堵上  
        for i in range(1, 10):  
            copy = getBoardCopy(board)  
            if isSpaceFree(copy, i):  
                makeMove(copy, playerLetter, i)  
                if isWinner(copy, playerLetter):  
                    return i  
      
      
        # 如果角上能落子的话,在角上落子  
        move = chooseRandomMoveFromList(board, [1, 3, 7, 9])  
        if move != None:  
            return move  
      
      
        # 如果能在中心落子的话,在中心落子  
        if isSpaceFree(board, 5):  
            return 5  
      
      
        # 在边上落子  
        return chooseRandomMoveFromList(board, [2, 4, 6, 8])  
      
      
    def isBoardFull(board):  
        # 如果棋盘满了,返回True  
        for i in range(1, 10):  
            if isSpaceFree(board, i):  
                return False  
        return True  
      
      
      
      
    print('Welcome to Tic Tac Toe!')  
      
      
    while True:  
        # 更新棋盘  
        theBoard = [' '] * 10  
        playerLetter, computerLetter = inputPlayerLetter()  
        turn = whoGoesFirst()  
        print('The ' + turn + ' will go first.')  
        gameIsPlaying = True  
      
      
        while gameIsPlaying:  
            if turn == 'player':  
                # 玩家回合  
                drawBoard(theBoard)  
                move = getPlayerMove(theBoard)  
                makeMove(theBoard, playerLetter, move)  
      
      
                if isWinner(theBoard, playerLetter):  
                    drawBoard(theBoard)  
                    print('Hooray! You have won the game!')  
                    gameIsPlaying = False  
                else:  
                    if isBoardFull(theBoard):  
                        drawBoard(theBoard)  
                        print('The game is a tie!')  
                        break  
                    else:  
                        turn = 'computer'  
      
      
            else:  
                # 电脑回合  
                move = getComputerMove(theBoard, computerLetter)  
                makeMove(theBoard, computerLetter, move)  
      
      
                if isWinner(theBoard, computerLetter):  
                    drawBoard(theBoard)  
                    print('The computer has beaten you! You lose.')  
                    gameIsPlaying = False  
                else:  
                    if isBoardFull(theBoard):  
                        drawBoard(theBoard)  
                        print('The game is a tie!')  
                        break  
                    else:  
                        turn = 'player'  
      
      
        if not playAgain():  
            break 
  • 相关阅读:
    【转】Java并发编程:阻塞队列
    【计算机二级Java语言】卷005
    【计算机二级Java语言】卷004
    【计算机二级Java语言】卷003
    【计算机二级Java语言】卷002
    【计算机二级Java语言】卷001
    【计算机二级C语言】卷020
    【计算机二级C语言】卷019
    【计算机二级C语言】卷017
    【计算机二级C语言】卷016
  • 原文地址:https://www.cnblogs.com/Leonardo-li/p/8743028.html
Copyright © 2011-2022 走看看