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  • hdu 5130(2014广州 圆与多边形相交模板)

    题意:一个很多个点p构成的多边形,pb <= pa * k时p所占区域与多边形相交面积

    设p(x,y),       (x - xb)^2+(y - yb)^2 / (x - xa)^2+(y - ya)^2  = k^2

    所以可以化成圆的一般式x^2 + y^2 + dx + ey + f = 0;

    推公式:

    圆心:(-d/2,-e/2)       半径:(sqrt(d*d + e*e - 4*f)) / 2

    得出圆后,套模板求圆与多边形的相交


    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <algorithm>
    #include <cmath>
    using namespace std;
    typedef long long ll;
    #define eps 1e-8
    #define N 100017
    
    struct Point
    {
        double x,y;
        Point(double x=0, double y=0):x(x),y(y) {}
        void get(int x1,int y1)
        {
            x = x1;
            y = y1;
        }
    };
    typedef Point Vector;
    struct Circle
    {
        Point c;
        double r;
        Circle() {}
        Circle(Point c,double r):c(c),r(r) {}
        Point point(double a)
        {
            return Point(c.x + cos(a)*r, c.y + sin(a)*r);
        }
        void input()
        {
            scanf("%lf%lf%lf",&c.x,&c.y,&r);
        }
    };
    int dcmp(double x)
    {
        if(x < -eps) return -1;
        if(x > eps) return 1;
        return 0;
    }
    template <class T> T sqr(T x)
    {
        return x * x;
    }
    Vector operator + (Vector A, Vector B)
    {
        return Vector(A.x + B.x, A.y + B.y);
    }
    Vector operator - (Vector A, Vector B)
    {
        return Vector(A.x - B.x, A.y - B.y);
    }
    Vector operator * (Vector A, double p)
    {
        return Vector(A.x*p, A.y*p);
    }
    Vector operator / (Vector A, double p)
    {
        return Vector(A.x/p, A.y/p);
    }
    bool operator < (const Point& a, const Point& b)
    {
        return a.x < b.x || (a.x == b.x && a.y < b.y);
    }
    bool operator >= (const Point& a, const Point& b)
    {
        return a.x >= b.x && a.y >= b.y;
    }
    bool operator <= (const Point& a, const Point& b)
    {
        return a.x <= b.x && a.y <= b.y;
    }
    bool operator == (const Point& a, const Point& b)
    {
        return dcmp(a.x-b.x) == 0 && dcmp(a.y-b.y) == 0;
    }
    double Dot(Vector A, Vector B)
    {
        return A.x*B.x + A.y*B.y;
    }
    double Length(Vector A)
    {
        return sqrt(Dot(A, A));
    }
    double Angle(Vector A, Vector B)
    {
        return acos(Dot(A, B) / Length(A) / Length(B));
    }
    double Cross(Vector A, Vector B)
    {
        return A.x*B.y - A.y*B.x;
    }
    Vector VectorUnit(Vector x)
    {
        return x / Length(x);
    }
    Vector Normal(Vector x)
    {
        return Point(-x.y, x.x) / Length(x);
    }
    double angle(Vector v)
    {
        return atan2(v.y, v.x);
    }
    
    bool OnSegment(Point P, Point A, Point B)
    {
        return dcmp(Cross(A-P,B-P)) == 0 && dcmp(Dot(A-P,B-P)) < 0;
    }
    double DistanceToSeg(Point P, Point A, Point B)
    {
        if(A == B) return Length(P-A);
        Vector v1 = B-A, v2 = P-A, v3 = P-B;
        if(dcmp(Dot(v1, v2)) < 0) return Length(v2);
        if(dcmp(Dot(v1, v3)) > 0) return Length(v3);
        return fabs(Cross(v1, v2)) / Length(v1);
    }
    double DistanceToLine(Point P, Point A, Point B)
    {
        Vector v1 = B-A, v2 = P-A;
        return fabs(Cross(v1,v2)) / Length(v1);
    }
    Point DisP(Point A, Point B)
    {
        return Length(B-A);
    }
    bool SegmentIntersection(Point A,Point B,Point C,Point D)
    {
        return max(A.x,B.x) >= min(C.x,D.x) &&
               max(C.x,D.x) >= min(A.x,B.x) &&
               max(A.y,B.y) >= min(C.y,D.y) &&
               max(C.y,D.y) >= min(A.y,B.y) &&
               dcmp(Cross(C-A,B-A)*Cross(D-A,B-A)) <= 0 &&
               dcmp(Cross(A-C,D-C)*Cross(B-C,D-C)) <= 0;
    }
    
    Point Zero = Point(0,0);
    double TriAngleCircleInsection(Circle C, Point A, Point B)
    {
        Vector OA = A-C.c, OB = B-C.c;
        Vector BA = A-B, BC = C.c-B;
        Vector AB = B-A, AC = C.c-A;
        double DOA = Length(OA), DOB = Length(OB),DAB = Length(AB), r = C.r;
        if(dcmp(Cross(OA,OB)) == 0) return 0;
        if(dcmp(DOA-C.r) < 0 && dcmp(DOB-C.r) < 0) return Cross(OA,OB)*0.5;
        else if(DOB < r && DOA >= r)
        {
            double x = (Dot(BA,BC) + sqrt(r*r*DAB*DAB-Cross(BA,BC)*Cross(BA,BC)))/DAB;
            double TS = Cross(OA,OB)*0.5;
            return asin(TS*(1-x/DAB)*2/r/DOA)*r*r*0.5+TS*x/DAB;
        }
        else if(DOB >= r && DOA < r)
        {
            double y = (Dot(AB,AC)+sqrt(r*r*DAB*DAB-Cross(AB,AC)*Cross(AB,AC)))/DAB;
            double TS = Cross(OA,OB)*0.5;
            return asin(TS*(1-y/DAB)*2/r/DOB)*r*r*0.5+TS*y/DAB;
        }
        else if(fabs(Cross(OA,OB)) >= r*DAB || Dot(AB,AC) <= 0 || Dot(BA,BC) <= 0)
        {
            if(Dot(OA,OB) < 0)
            {
                if(Cross(OA,OB) < 0) return (-acos(-1.0)-asin(Cross(OA,OB)/DOA/DOB))*r*r*0.5;
                else                 return ( acos(-1.0)-asin(Cross(OA,OB)/DOA/DOB))*r*r*0.5;
            }
            else                     return asin(Cross(OA,OB)/DOA/DOB)*r*r*0.5;
        }
        else
        {
            double x = (Dot(BA,BC)+sqrt(r*r*DAB*DAB-Cross(BA,BC)*Cross(BA,BC)))/DAB;
            double y = (Dot(AB,AC)+sqrt(r*r*DAB*DAB-Cross(AB,AC)*Cross(AB,AC)))/DAB;
            double TS = Cross(OA,OB)*0.5;
            return (asin(TS*(1-x/DAB)*2/r/DOA)+asin(TS*(1-y/DAB)*2/r/DOB))*r*r*0.5 + TS*((x+y)/DAB-1);
        }
    }
    
    Point p[2000];
    
    int main()
    {
        int n;
        double k;
        int cas = 1;
        while(scanf("%d%lf",&n,&k) != EOF)
        {
            for(int i = 1; i <= n; i++)
            {
                double x,y;
                scanf("%lf%lf",&x,&y);
                p[i].get(x,y);
            }
            p[n+1] = p[1];
            double x1,x2,y1,y2;
            scanf("%lf%lf%lf%lf",&x1,&y1,&x2,&y2);
    
            double d = (2.0*k*k*x1-2.0*x2)/(1.0-k*k);
            double e = (2.0*k*k*y1-2.0*y2)/(1.0-k*k);
            double f = (x2*x2+y2*y2-k*k*(x1*x1+y1*y1))/(1.0-k*k);
            Point O = Point(-d*0.5,-e*0.5);
            double R= sqrt(d*d+e*e-4.0*f)*0.5;
            Circle C = Circle(O,R);
            double ans = 0.0;
            for(int i=1; i<=n; i++)
                ans += TriAngleCircleInsection(C, p[i], p[i+1]);
            printf("Case %d: %.10f
    ",cas++,fabs(ans));
        }
        return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/Przz/p/5409733.html
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