【题干描述】
Given a matrix A, return the transpose of A.
The transpose of a matrix is the matrix flipped over it's main diagonal, switching the row and column indices of the matrix.(一矩阵A，返回其转置)
【思路】
- 直接处理，A[i][j]的值赋值给output[j][i].
【python代码】
1 input = [[1, 2, 3], [4, 5, 6]] 2 row = len(input) 3 col = len(input[0]) 4 5 output = [[None]*row for _ in range(col)] 6 7 for j in range(col): 8 for i in range(row): 9 output[j][i] = input[i][j] 10 print output
【所用python点】
- range()和xrange()的区别：https://www.cnblogs.com/Sinkinghost/p/9320070.html
- [[None]*row for _ in range(col)] 的 “_” 其实可以用 任意变量替换。
- [None]*row 的结果是[None, None, None]