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  • poj2109

    题目链接: http://poj.org/problem?id=2109

    代码很简单,但是还是学到了东西。。

    类型             长度 (bit)            有效数字                    绝对值范围
    float             32                      6~7                  10^(-37) ~ 10^38
    double          64                     15~16               10^(-307) ~10^308
    long double   128                   18~19                10^(-4931) ~ 10 ^ 4932

    AC代码:

    1 #include<stdio.h>
    2 #include<math.h>
    3 int main(){
    4     double n,p;
    5     while(~scanf("%lf%lf",&n,&p)){
    6         printf("%.0lf
    ",pow(p,1/n));
    7     }
    8 }


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  • 原文地址:https://www.cnblogs.com/Stomach-ache/p/3703227.html
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