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  • MySQL学习 (三) Limit-Distinct-Union

    MySQL学习 (三) Limit-Distinct-Union

    Limit

    简介

    • 限制获得的记录数量
    mysql> SELECT * FROM teacher_class limit 1;
    +----+--------+--------+-----------+------+------+------------+------------+
    | id | t_name | gender | c_name    | room | days | begin_date | end_date   |
    +----+--------+--------+-----------+------+------+------------+------------+
    |  1 | Gene   | male   | python001 | 334  |   22 | 2013-03-31 | 2013-05-05 |
    +----+--------+--------+-----------+------+------+------------+------------+
    1 row in set (0.00 sec)
    

    语法

    Limit offset, row_count
    
    # offset 偏移量,从0开始;
    # row_count,总记录数,长度,不是开始和结束, 如果数量大于余下的记录数,则获取所有余下的记录数,默认值0
    
    mysql> SELECT * FROM teacher_class limit 3,4;
    +----+---------+--------+-----------+------+------+------------+------------+
    | id | t_name  | gender | c_name    | room | days | begin_date | end_date   |
    +----+---------+--------+-----------+------+------+------------+------------+
    |  4 | Emma    | female | python004 | 338  |   20 | 2013-03-15 | 2013-04-05 |
    |  5 | Janice  | female | python007 | 332  |   27 | 2013-04-15 | 2013-05-10 |
    |  6 | Jessica | female | python008 | 332  |   28 | 2013-05-15 | 2013-06-08 |
    +----+---------+--------+-----------+------+------+------------+------------+
    3 rows in set (0.00 sec)
    

    Distinct

    简介

    • distinct: 去掉重复记录, 指的是字段值,都相同的记录,而不是部分字段相同的记录
    • All: 表示所有,默认就是all的行为
    mysql> SELECT days FROM teacher_class;
    +------+
    | days |
    +------+
    |   22 |
    |   22 |
    |   55 |
    |   20 |
    |   27 |
    |   28 |
    +------+
    6 rows in set (0.00 sec)
    
    mysql> SELECT DISTINCT days FROM teacher_class;
    +------+
    | days |
    +------+
    |   22 |
    |   55 |
    |   20 |
    |   27 |
    |   28 |
    +------+
    5 rows in set (0.00 sec)
    
    mysql> SELECT days, begin_date FROM teacher_class;
    +------+------------+
    | days | begin_date |
    +------+------------+
    |   22 | 2013-03-31 |
    |   22 | 2013-05-31 |
    |   55 | 2013-02-15 |
    |   20 | 2013-03-15 |
    |   27 | 2013-04-15 |
    |   28 | 2013-05-15 |
    +------+------------+
    6 rows in set (0.01 sec)
    
    mysql> SELECT DISTINCT days, begin_date FROM teacher_class;
    +------+------------+
    | days | begin_date |
    +------+------------+
    |   22 | 2013-03-31 |
    |   22 | 2013-05-31 |
    |   55 | 2013-02-15 |
    |   20 | 2013-03-15 |
    |   27 | 2013-04-15 |
    |   28 | 2013-05-15 |
    +------+------------+
    6 rows in set (0.00 sec)
    

    union联合查询

    简介

    • 将多条select语句的结果,合并到一起,称为联合

    • 使用union关键字,联合两个select语句即可

    • 注意 如果union查询结果有重复,会自动去掉重复的数据;如果想得到全部数据,通过UNION ALL来显示数据

    • 多个select语句检索时,字段要一致; 数据类型,尽量保持一致;如果不一致,应该能让MySQL能够做类型转换

    • 检索结果列名称的问题:根据第一条select语句的字段,进行名称排列

    • 场景

      1. 获得数据的条件,出现逻辑冲突,或者很难在一个逻辑内表示,不好拆分,分成多个逻辑,分别实现,然后合并到一起
    mysql> SELECT t_name, days FROM teacher_class WHERE c_name = "python002" ORDER BY days DESC LIMIT 1;
    +---------+------+
    | t_name  | days |
    +---------+------+
    | Jessica |   55 |
    +---------+------+
    1 row in set (0.00 sec)
    
    mysql>
    mysql> SELECT t_name, days FROM teacher_class WHERE c_name = "python008" ORDER BY days DESC LIMIT 1;
    +---------+------+
    | t_name  | days |
    +---------+------+
    | Jessica |   28 |
    +---------+------+
    1 row in set (0.00 sec)
    
    # 联合查询语法
    
    mysql>(SELECT t_name, days FROM teacher_class WHERE c_name = "python002" ORDER BY days DESC LIMIT 1) UNION (SELECT t_name, days FROM teacher_class WHERE c_name = "python008" ORDER BY days DESC LIMIT 1);
    +---------+------+
    | t_name  | days |
    +---------+------+
    | Jessica |   55 |
    | Jessica |   28 |
    +---------+------+
    2 rows in set (0.00 sec)
    
    

    子语句的结果排序

    1. 将子语句包裹在括号里
    2. 子语句的order by需要使用limit才能生效,否则,排序失效

    所有结果进行排序

    1. 只需要在最后一个select子语句后,使用ORDER BY进行排序
    mysql> (SELECT t_name, days FROM teacher_class WHERE c_name = "python002" ) 
        -> UNION (SELECT t_name, days FROM teacher_class WHERE c_name = "python008" ) ORDER BY days;
    +---------+------+
    | t_name  | days |
    +---------+------+
    | Mona    |   22 |
    | Emma    |   28 |
    | Jessica |   28 |
    | Mona    |   55 |
    | Jessica |   55 |
    +---------+------+
    5 rows in set (0.00 sec)
    
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  • 原文地址:https://www.cnblogs.com/Tcorner/p/11474494.html
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