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  • [解题报告]HDU 1012 u Calculate e

    u Calculate e

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 21753    Accepted Submission(s): 9604


    Problem Description
    A simple mathematical formula for e is



    where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
     
    Output
    Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
     
    Sample Output
    n e - ----------- 0 1 1 2 2 2.5 3 2.666666667 4 2.708333333
     
    Source
     
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    不要企图去算n=0;

    #include<stdio.h>
    int main()
    {
        double i,j,x,s=1;
        printf("n e\n- -----------\n0 1\n");
        for(i=1;i<10;i++)
        {
            printf("%lg ",i);
            x=1;
            for(j=1;j<=i;j++)
            x*=1/j;
            s+=x;
            if(i==8)
            {
                printf("%.9lf\n",s);
                continue;
            }
            printf("%.10lg\n",s);
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/TheLaughingMan/p/2958345.html
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