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  • hdu 2138 How many prime numbers

    How many prime numbers

    http://acm.hdu.edu.cn/showproblem.php?pid=2138

    Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
    Total Submission(s): 19579    Accepted Submission(s): 6696

    Problem Description
      Give you a lot of positive integers, just to find out how many prime numbers there are.
     
    Input
      There are a lot of cases. In each case, there is an integer N representing the number of integers to find. Each integer won’t exceed 32-bit signed integer, and each of them won’t be less than 2.
     
    Output
      For each case, print the number of prime numbers you have found out.
     
    Sample Input
    3
    2
    3
    4
     
    Sample Output
    2
     
    Author
    wangye
     
    Source
     
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    Miller_Rabin
    测试 15次TLE,5次A了
    有谁知道他的时间复杂度吗?
    #include<ctime>
    #include<cstdio>
    #include<cstdlib>
    using namespace std;
    typedef long long LL;
    int n,ans;
    LL p;
    LL mul(LL a,LL b)
    {
        LL r=0;
        while(b)
        {
            if(b&1) b--,r+=a,r%=p;
            a<<=1; a%=p; b>>=1;
        }
        return r;
    }
    LL qm(LL a,LL b)
    {
        LL r=1;
        while(b)
        {
            if(b&1) r=mul(r,a);
            b>>=1; a=mul(a,a);
        }
        return r;
    }
    bool Miller_Rabin()
    {
        if(p==2) return true;
        if(p%2==0) return false;
        int T=5;
        LL m=p-1,k=0,a,x,y;
        while(m%2==0) k++,m>>=1;
        while(T--)
        {
            a=rand()%(p-1)+1;
            x=qm(a,m);
            for(int i=1;i<=k;i++)
            {
                y=mul(x,x);
                if(x&1 && y==1 && x!=1 && x!=-1) return false;
                x=y;
            }
            if(x!=1) return false;
        }
        return true;
    }
    int main()
    {
        srand(time(0));
        while(scanf("%d",&n)!=EOF)
        {
            ans=0; 
            while(n--)
            {
                scanf("%lld",&p);
                if(Miller_Rabin()) ans++;
            }
            printf("%d
    ",ans);
        }
    }
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  • 原文地址:https://www.cnblogs.com/TheRoadToTheGold/p/7341568.html
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