UVA 621 Secret Research

额。。 不理解这题为什么会是数学题 0.0 可能是输入中有很长的字符串需要处理，然后获得字符串的位数是一个需要技巧的过程？ 不过我直接STL过的 。。。真心感觉STL很方便 但是也不能依赖STL额。。顺便总结一下输出的时候如果没要求最后不输出回车 最后一定要输出回车 否则就会WAWAWA 我在这栽了三次 = =

以下是题和AC代码

  Secret Research 

At a certain laboratory results of secret research are thoroughly encrypted. A result of a single experiment is stored as an information of its completion:

`positive result', `negative result', `experiment failed' or `experiment not completed'

The encrypted result constitutes a string of digits S, which may take one of the following forms:

positive result 		 S = 1 or S = 4 or S = 78 

negative result 		 S = S35 

experiment failed 		 S = 9S4 

experiment not completed 		 S = 190S

(A sample result S35 means that if we add digits 35 from the right hand side to a digit sequence then we shall get the digit sequence corresponding to a failed experiment)

You are to write a program which decrypts given sequences of digits.

Input 

A integer n stating the number of encrypted results and then consecutive n lines, each containing a sequence of digits given as ASCII strings.

Output 

For each analysed sequence of digits the following lines should be sent to output (in separate lines):

		 + 		  for a positive result
		 - 		  for a negative result
		 * 		  for a failed experiment
		 ? 		  for a not completed experiment

In case the analysed string does not determine the experiment result, a first match from the above list should be outputted.

Sample Input 

4
78
7835
19078
944

Sample Output 

+
-
?
*

#include<iostream>
#include<string>
#include<stdlib.h>
#include<stdio.h>
using namespace std;

int main(void)
{
    //freopen("621.in", "r", stdin);
    long long n;
    scanf("%lld", &n);
    for (long long i = 0; i < n; i++)
    {
        string s;
        int flag;
        cin >> s;
        if (s == "1" || s == "4" || s == "78") { printf("+
");  continue; }
        else if (s[s.size() - 1] == '5' && s[s.size() - 2] == '3') { printf("-
"); continue; }
        else if (s[0] == '9' && s[s.size() - 1] == '4') { printf("*
");  continue; }
        else if (s[0] == '1' && s[1] == '9' && s[2] == '0') { printf("?
");  continue; }
        
    }
    //system("pause");
    return 0;
}