zoukankan      html  css  js  c++  java
  • leetcode[134]Gas Station

    There are N gas stations along a circular route, where the amount of gas at station i is gas[i].

    You have a car with an unlimited gas tank and it costs cost[i] of gas to travel from station i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations.

    Return the starting gas station's index if you can travel around the circuit once, otherwise return -1.

    Note:
    The solution is guaranteed to be unique.

    class Solution {
    public:
        int canCompleteCircuit(vector<int> &gas, vector<int> &cost) {
            if(gas.empty())return -1;
            int len=gas.size();
            int gasLeft=0;
            int begin=0,end=0;
            int i=0;
            for(int j=0;j<len;j++)
            {
                gasLeft+=gas[i]-cost[i];
                if(j==len-1)break;
                if(gasLeft>=0)
                {
                    end++;
                    i=end;
                }
                else
                {
                    begin=begin==0?len-1:--begin;
                    i=begin;
                }
            }
            return gasLeft>=0?begin:-1;
        }
    };
  • 相关阅读:
    ansible 批量在远程主机上执行命令
    SQLAlchemy
    operator, itertools
    mongodb基础语法
    django model Meta选项
    __getattr__,settr
    django的contenttype表
    time和datetime和tzinfo
    全局钩子的改名
    dom中文字居中
  • 原文地址:https://www.cnblogs.com/Vae1990Silence/p/4281252.html
Copyright © 2011-2022 走看看