思路:
5分代码
Tip:
无
#include <bits/stdc++.h>
using namespace std;
const int maxn = 100000 + 5;
int main() {
long long n, m;
cin >> n >> m;
if(n==1)
cout << 1 << endl;
else if (n % 2 != 0)
cout << 36 << endl;
return 0;
}