zoukankan      html  css  js  c++  java
  • JAVA语法基础作业——动手动脑以及课后实验性问题 (五)

    一、请编写程序将整数转换为汉字读法字符串

     1 import java.util.Scanner;
     2 
     3 public class Test {
     4 
     5 public static void main(String[] args) {
     6     Scanner in=new Scanner(System.in);
     7     System.out.println("输入一个数:");
     8     double a;
     9     a=in.nextDouble();
    10     System.out.println(digitUppercase(a));
    11 }
    12 public static String digitUppercase(double n) { 
    13     String fraction[] = { "角", "分"}; 
    14     String digit[] = { "零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖"}; 
    15     String unit[][] = { { "元", "万", "亿"}, { "", "拾", "佰", "仟"}}; 
    16 
    17     String head = n < 0 ? "负" : ""; 
    18     n = Math.abs(n); 
    19 
    20     String s = ""; 
    21     for (int i = 0; i < fraction.length; i++) { 
    22         s += (digit[(int) (Math.floor(n * 10 * Math.pow(10, i)) % 10)] + fraction[i]).replaceAll("(零.)+", ""); 
    23     } 
    24     if (s.length() < 1) { 
    25         s = "整"; 
    26     } 
    27     int integerPart = (int) Math.floor(n); 
    28 
    29     for (int i = 0; i < unit[0].length && integerPart > 0; i++) { 
    30         String p = ""; 
    31     for (int j = 0; j < unit[1].length && n > 0; j++) { 
    32         p = digit[integerPart % 10] + unit[1][j] + p; 
    33         integerPart = integerPart / 10; 
    34         } 
    35     s = p.replaceAll("(零.)*零$", "").replaceAll("^$", "零") + unit[0][i] + s; 
    36     } 
    37     return head + s.replaceAll("(零.)*零元", "元").replaceFirst("(零.)+", "").replaceAll("(零.)+", "零").replaceAll("^整$", "零元整"); 
    38     } 
    39 
    40 }

     程序截图:

    、数组表示大数

      1 import java.util.Scanner;
      2 
      3 public class Dashu {
      4 
      5 public static void main(String[] args) {
      6     // TODO Auto-generated method stub
      7     String s1,s2;
      8     Scanner in=new Scanner(System.in);
      9     System.out.println("输入第一个大数:");
     10     s1=in.next();
     11     System.out.println("输入第二个大数:");
     12     s2=in.next();
     13     System.out.println(add(s1,s2));
     14     System.out.println(sub(s1,s2));
     15 
     16 }
     17 
     18 private static String add(String a, String b){ 
     19     System.out.print("加法:" + a+ "+" + b + "=");
     20     char[] aa = new StringBuffer(a).reverse().toString().toCharArray(); 
     21     char[] bb = new StringBuffer(b).reverse().toString().toCharArray(); 
     22     int aLen = aa.length; 
     23     int bLen = bb.length; 
     24 
     25     int len = aLen > bLen ? aLen : bLen; 
     26 
     27     int[] result = new int[len + 1]; 
     28     for (int i = 0; i < len + 1; ++i) { 
     29     int aint = i < aLen ? aa[i] - '0' : 0; 
     30     int bint = i < bLen ? bb[i] - '0' : 0; 
     31     result[i] = aint + bint; 
     32     } 
     33 
     34     for(int i=0;i<result.length-1;++i){ 
     35         if(result[i]>=10){
     36             result[i+1] += result[i]/10; 
     37             result[i] %= 10; 
     38             } 
     39     } 
     40 
     41     boolean flag = true; 
     42     StringBuffer sb = new StringBuffer(len); 
     43     for(int i=len;i>=0;--i){ 
     44         if(result[i]==0&&flag){ 
     45             continue; 
     46             }
     47         else{ 
     48             flag=false; 
     49             } 
     50         sb.append(result[i]); 
     51         } 
     52         return sb.toString(); 
     53         } 
     54     public static String sub(String f, String s){ 
     55         System.out.print("减法:" + f + "-" + s + "="); 
     56         // 将字符串翻转并转换成字符数组 
     57         char[] a = new StringBuffer(f).reverse().toString().toCharArray(); 
     58         char[] b = new StringBuffer(s).reverse().toString().toCharArray(); 
     59         int lenA = a.length; 
     60         int lenB = b.length; 
     61         int len = lenA > lenB ? lenA : lenB; 
     62         int[] result = new int[len];  
     63         char sign = '+';  
     64         if (lenA < lenB) { 
     65             sign = '-'; 
     66         } 
     67         else if (lenA == lenB){
     68             int i = lenA - 1; 
     69             while (i > 0 && a[i] == b[i]) { 
     70                 i--; 
     71             } 
     72             if (a[i] < b[i]) { 
     73                 sign = '-'; 
     74             } 
     75         } 
     76         for (int i = 0; i < len; i++) { 
     77             int aint = i < lenA ? (a[i] - '0') : 0; 
     78             int bint = i < lenB ? (b[i] - '0') : 0; 
     79             if (sign == '+') { 
     80                 result[i] = aint - bint; 
     81             } 
     82             else { 
     83                 result[i] = bint - aint; 
     84             } 
     85         } 
     86         for (int i = 0; i < result.length - 1; i++) { 
     87             if (result[i] < 0) { 
     88                 result[i + 1] -= 1; 
     89                 result[i] += 10; 
     90             } 
     91         } 
     92 
     93         StringBuffer sb = new StringBuffer(); 
     94         if (sign == '-') { 
     95             sb.append('-'); 
     96         }  
     97         boolean flag = true; 
     98         for (int i = len - 1; i >= 0; i--) { 
     99             if (result[i] == 0 && flag) { 
    100                 continue; 
    101             } 
    102             else { 
    103                 flag = false; 
    104             } 
    105             sb.append(result[i]); 
    106         } 
    107         if (sb.toString().equals("")) { 
    108             sb.append("0"); 
    109         } 
    110         System.out.println(sb.toString()); 
    111         return sb.toString(); 
    112     } 
    113 }

    程序截图:

    三、随机生成10个数,填充一个数组,然后用消息框显示数组内容,接着计算数组元素的和,将结果也显示在消息框中

     1 import javax.swing.JOptionPane;
     2 
     3 public class Shuzu {
     4 
     5 public static void main(String[] args) {
     6     // TODO Auto-generated method stub
     7     int a[],sum=0;
     8     a=new int[10];
     9     String output=new String();
    10     for(int i=0;i<a.length;i++){
    11         a[i]=(int)(Math.random()*100);
    12         }
    13     output+="a[10]={";
    14     for(int i=0;i<a.length;i++){
    15         output+=a[i]+" ";
    16         }
    17     output+="}";
    18     for(int i=0;i<a.length;i++){
    19         sum+=a[i];
    20         }
    21     output+="
    sum:"+sum;
    22     JOptionPane.showMessageDialog(null, output,"结果",
    23     JOptionPane.PLAIN_MESSAGE);
    24     }
    25 }

    程序截图:

     

    设计思想:

    随机产生10个相加数求和。

  • 相关阅读:
    为Jupyter只安装目录的扩展包
    前端菜鸟的小程序摸索记录
    小计:Shopee批量删除修复~附脚本
    Python3 与 C# 并发编程之~ 协程篇
    记一次硬件故障,并普及点硬件知识
    小计:协同办公衍生出的需求
    监控MySQL|Redis|MongoDB的执行语句(go-sniffer)
    Linux IO实时监控iostat命令详解
    Linux下的磁盘缓存
    使用top命令查看系统状态
  • 原文地址:https://www.cnblogs.com/XiaoPiHaiEr/p/6036598.html
Copyright © 2011-2022 走看看