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  • 一个洗牌程序算法,随机交换位置 【转】

     int[] numbers=new int [20];     //建立一个数组
                Random rand=new Random (); //生成随机数
                string result="";                    //保存结果
                for (int i = 0; i < 20; i++)       //初始化数组
                    numbers[i] = i+1;
                for (int i = 0; i < 20; i++)          //洗牌
                  {
                    int temp = rand.Next(20);
                    int tempNumber = numbers[i ];
                    numbers[i] = numbers[temp ];
                    numbers[temp] =tempNumber ;
                  }
                for (int i = 0; i < 4; i++)          //这个用来排列你想要的那4个数
                    for (int j = 0; j < 4; j++)         
                    {                                           //你不需要就去掉它
                        int temp;
                        if (numbers[i] < numbers[j])
                        {
                            temp = numbers[j];
                            numbers[j] = numbers[i];
                            numbers[i] = temp;
                        }
                        else
                            continue;
                    }                                         //生成结果项
                        for (int i = 0; i < 4; i++)
                            result += "result" + i.ToString() + "==>" + numbers[i].ToString() + Environment.NewLine;
                          MessageBox.Show(result );     //输出结果

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  • 原文地址:https://www.cnblogs.com/Yellowshorts/p/2917090.html
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