SCUT

https://scut.online/p/297

一般的树剖是关于点权的，但是突发奇想好像边权也是一样的。做一些小改动。

#include<bits/stdc++.h>
#define lc (o<<1)
#define rc (o<<1|1)
typedef long long ll;
using namespace std;

const ll INF = 1e18;

const int MAXN = 125000 + 5;
int dep[MAXN], siz[MAXN],  son[MAXN], fa[MAXN], top[MAXN], tid[MAXN], rnk[MAXN], cnt;

int n, m;

int head[MAXN], etop;
struct Edge {
    int v, next;
} e[MAXN * 2];

inline void init(int n) {
    etop = 0;
    memset(head, -1, sizeof(head[0]) * (n + 1));
}

inline void addedge(int u, int v) {
    e[++etop].v = v;
    e[etop].next = head[u];
    head[u] = etop;
    e[++etop].v = u;
    e[etop].next = head[v];
    head[v] = etop;
}

struct SegmentTree {
    ll mi[MAXN * 4], ma[MAXN * 4], lz[MAXN * 4];

    void pushup(int o) {
        mi[o] = min(mi[lc], mi[rc]);
        ma[o] = max(ma[lc], ma[rc]);
    }

    void pushdown(int o, int l, int r) {
        if(lz[o]) {
            lz[lc] += lz[o];
            lz[rc] += lz[o];
            mi[lc] += lz[o];
            ma[lc] += lz[o];
            mi[rc] += lz[o];
            ma[rc] += lz[o];
            lz[o] = 0;
        }
    }

    void update(int o, int l, int r, int ql, int qr, int v) {
        if(ql <= l && r <= qr) {
            lz[o] += v, mi[o] += v, ma[o] += v;
        } else {
            pushdown(o, l, r);
            int m = (l + r) >> 1;
            if(ql <= m)
                update(lc, l, m, ql, qr, v);
            if(qr >= m + 1)
                update(rc, m + 1, r, ql, qr, v);
            pushup(o);
        }
    }

    ll querymin(int o, int l, int r, int ql, int qr) {
        if(ql <= l && r <= qr) {
            return mi[o];
        } else {
            pushdown(o, l, r);
            int m = (l + r) >> 1;
            ll res = INF;
            if(ql <= m)
                res = min(res, querymin(lc, l, m, ql, qr));
            if(qr >= m + 1)
                res = min(res, querymin(rc, m + 1, r, ql, qr));
            return res;
        }
    }
    ll querymax(int o, int l, int r, int ql, int qr) {
        if(ql <= l && r <= qr) {
            return ma[o];
        } else {
            pushdown(o, l, r);
            int m = (l + r) >> 1;
            ll res = -INF;
            if(ql <= m)
                res = max(res, querymax(lc, l, m, ql, qr));
            if(qr >= m + 1)
                res = max(res, querymax(rc, m + 1, r, ql, qr));
            return res;
        }
    }
} st;

void init1() {
    dep[1] = 1;
}

void dfs1(int u, int t) {
    siz[u] = 1, son[u] = -1, fa[u] = t;
    for(int i = head[u]; i != -1; i = e[i].next) {
        int v = e[i].v;
        if(v == t)
            continue;
        dep[v] = dep[u] + 1;
        dfs1(v, u);
        siz[u] += siz[v];
        if(son[u] == -1 || siz[v] > siz[son[u]])
            son[u] = v;
    }
}

void init2() {
    cnt = 0;
}

void dfs2(int u, int t) {
    top[u] = t;
    tid[u] = ++cnt;
    rnk[cnt] = u;
    if(son[u] == -1)
        return;
    dfs2(son[u], t);
    for(int i = head[u]; i != -1; i = e[i].next) {
        int v = e[i].v;
        if(v == fa[u] || v == son[u])
            continue;
        dfs2(v, v);
    }
}

ll querymin1(int u, int v) {
    ll ret = INF;
    int tu = top[u], tv = top[v];
    while(tu != tv) {
        if(dep[tu] >= dep[tv]) {
            ret = min(ret, st.querymin(1, 1, n, tid[tu], tid[u]));
            u = fa[tu];
            tu = top[u];
        } else {
            ret = min(ret, st.querymin(1, 1, n, tid[tv], tid[v]));
            v = fa[tv];
            tv = top[v];
        }
    }
    if(tid[u] == tid[v])
        return ret;
    if(tid[u] < tid[v])
        ret = min(ret, st.querymin(1, 1, n, tid[u], tid[v] - 1));
    else
        ret = min(ret, st.querymin(1, 1, n, tid[v], tid[u] - 1));
    return ret;
}

ll querymax1(int u, int v) {
    ll ret = -INF;
    int tu = top[u], tv = top[v];
    while(tu != tv) {
        if(dep[tu] >= dep[tv]) {
            ret = max(ret, st.querymax(1, 1, n, tid[tu], tid[u]));
            u = fa[tu];
            tu = top[u];
        } else {
            ret = max(ret, st.querymax(1, 1, n, tid[tv], tid[v]));
            v = fa[tv];
            tv = top[v];
        }
    }
    if(tid[u] == tid[v])
        return ret;
    if(tid[u] < tid[v])
        ret = max(ret, st.querymax(1, 1, n, tid[u], tid[v] - 1));
    else
        ret = max(ret, st.querymax(1, 1, n, tid[v], tid[u] - 1));
    return ret;
}

inline void update1(int u, int v, int val) {
    int tu = top[u], tv = top[v];
    while(tu != tv) {
        if(dep[tu] >= dep[tv]) {
            st.update(1, 1, n, tid[tu], tid[u], val);
            u = fa[tu];
            tu = top[u];
        } else {
            st.update(1, 1, n, tid[tv], tid[v], val);
            v = fa[tv];
            tv = top[v];
        }
    }
    if(tid[u] == tid[v])
        return;
    else if(tid[u] < tid[v])
        st.update(1, 1, n, tid[u], tid[v] - 1, val);
    else
        st.update(1, 1, n, tid[v], tid[u] - 1, val);
}

void op0() {
    int u, v, val;
    scanf("%d%d%d", &u, &v, &val);
    update1(u, v, val);
}

void op1() {
    int u, v;
    scanf("%d%d", &u, &v);
    ll res = querymin1(u, v);
    if(res != 0) {
        printf("Lunatic
");
    } else {
        res = querymax1(u, v);
        if(res != 0)
            printf("Lunatic
");
        else
            printf("Normal
");
    }
}


int main() {
#ifdef Yinku
    freopen("Yinku.in", "r", stdin);
#endif // Yinku
    scanf("%d", &n);
    init(n);
    for(int i = 1, u, v; i <= n - 1; ++i) {
        scanf("%d%d", &u, &v);
        addedge(u, v);
    }
    init1();
    dfs1(1, -1);
    init2();
    dfs2(1, 1);
    scanf("%d", &m);
    for(int i = 1, op; i <= m; ++i) {
        scanf("%d", &op);
        switch(op) {
            case 0:
                op0();
                break;
            case 1:
                op1();
                break;
        }
    }
    return 0;
}

上面的那个代码是有问题的，算法和定义不对应，但是居然能过？数据太弱了笑死我了。