codeforces round #419 A. Karen and Morning

Karen is getting ready for a new school day!

It is currently hh:mm, given in a 24-hour format. As you know, Karen loves palindromes, and she believes that it is good luck to wake up when the time is a palindrome.

What is the minimum number of minutes she should sleep, such that, when she wakes up, the time is a palindrome?

Remember that a palindrome is a string that reads the same forwards and backwards. For instance, 05:39 is not a palindrome, because 05:39 backwards is 93:50. On the other hand, 05:50 is a palindrome, because 05:50 backwards is 05:50.

Input

The first and only line of input contains a single string in the format hh:mm (00 ≤  hh  ≤ 23, 00 ≤  mm  ≤ 59).

Output

Output a single integer on a line by itself, the minimum number of minutes she should sleep, such that, when she wakes up, the time is a palindrome.

Examples

input

05:39

output

11

input

13:31

output

0

input

23:59

output

1

Note

In the first test case, the minimum number of minutes Karen should sleep for is 11. She can wake up at 05:50, when the time is a palindrome.

In the second test case, Karen can wake up immediately, as the current time, 13:31, is already a palindrome.

In the third test case, the minimum number of minutes Karen should sleep for is 1 minute. She can wake up at 00:00, when the time is a palindrome.

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
char s[12];int n;
bool check()
{
    int l=1,r=n;
    while(l<r)
    {
        if(s[l]!=s[r])return false;
        l++;r--;
    }
    return true;
}
int main()
{
    scanf("%s",s+1);
    n=strlen(s+1);
    int ans=0;
    while(1)
    {
        if(check())
        {
            printf("%d",ans);
            return 0;
        }
        s[5]++;ans++;
        if(s[5]=='9'+1)s[5]='0',s[4]++;
        if(s[4]=='6')s[4]='0',s[2]++;
        if(s[2]=='9'+1 && s[1]<='1')s[1]++,s[2]='0';
        if(s[2]=='4' && s[1]=='2')s[1]='0',s[2]='0';
    }
    return 0;
}