zoukankan      html  css  js  c++  java
  • The Suspects(POJ 1611 并查集)

    The Suspects
    Time Limit: 1000MS   Memory Limit: 20000K
    Total Submissions: 30158   Accepted: 14665

    Description

    Severe acute respiratory syndrome (SARS), an atypical pneumonia of unknown aetiology, was recognized as a global threat in mid-March 2003. To minimize transmission to others, the best strategy is to separate the suspects from others.
    In the Not-Spreading-Your-Sickness University (NSYSU), there are many student groups. Students in the same group intercommunicate with each other frequently, and a student may join several groups. To prevent the possible transmissions of SARS, the NSYSU collects the member lists of all student groups, and makes the following rule in their standard operation procedure (SOP).
    Once a member in a group is a suspect, all members in the group are suspects.
    However, they find that it is not easy to identify all the suspects when a student is recognized as a suspect. Your job is to write a program which finds all the suspects.

    Input

    The input file contains several cases. Each test case begins with two integers n and m in a line, where n is the number of students, and m is the number of groups. You may assume that 0 < n <= 30000 and 0 <= m <= 500. Every student is numbered by a unique integer between 0 and n−1, and initially student 0 is recognized as a suspect in all the cases. This line is followed by m member lists of the groups, one line per group. Each line begins with an integer k by itself representing the number of members in the group. Following the number of members, there are k integers representing the students in this group. All the integers in a line are separated by at least one space.
    A case with n = 0 and m = 0 indicates the end of the input, and need not be processed.

    Output

    For each case, output the number of suspects in one line.

    Sample Input

    100 4  //n个学生,m个分组
    2 1 2  //该分组k人,分别...
    5 10 13 11 12 14
    2 0 1
    2 99 2    //假如0感染后,哪些人也会被感染或间接感染
    200 2
    1 5
    5 1 2 3 4 5
    1 0
    0 0

    Sample Output

    4
    1
    1
     1 #include <iostream>
     2 #include <cstdio>
     3 #include <cstring>
     4 #include <algorithm>
     5 using namespace std;
     6 #define Max 30005
     7 int par[Max],num[Max];
     8 int find(int x)
     9 {
    10     if(par[x]!=x)
    11         return par[x]=find(par[x]);
    12     return par[x];
    13 }
    14 void unite(int x,int y)
    15 {
    16     x=find(x);
    17     y=find(y);
    18     if(x!=y)
    19     {
    20         par[x]=y;
    21         num[y]+=num[x];
    22     }
    23     return;
    24 }
    25 int main()
    26 {
    27     int n,m;
    28     int a,b,k;
    29     int i,j;
    30     freopen("in.txt","r",stdin);
    31     while(scanf("%d%d",&n,&m))
    32     {
    33         if(n==0&&m==0)
    34             break;
    35         for(i=0;i<Max;i++)
    36         {
    37             par[i]=i;
    38             num[i]=1;
    39         }
    40         for(i=0;i<m;i++)
    41         {
    42             scanf("%d",&k);
    43             for(j=0;j<k;j++)
    44             {
    45                 if(j==0)
    46                     scanf("%d",&a);
    47                 else
    48                 {
    49                     scanf("%d",&b);
    50                     unite(a,b);
    51                 }
    52             }
    53         }
    54         printf("%d
    ",num[find(0)]);
    55     }
    56 }
  • 相关阅读:
    jquery.autocomplete.js 插件的自定义搜索规则
    经测试可用的汉字转拼音及汉字取首字母
    微信小程序UI学习
    微信小程序的生命周期和APP对象的使用
    微信小程序的配置详解
    微信小程序事件
    视图和渲染
    微信小程序<一>
    JS实战篇
    获取重复字符串的range,设置attributedText
  • 原文地址:https://www.cnblogs.com/a1225234/p/5264860.html
Copyright © 2011-2022 走看看