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  • [转]MySQL常用查询

    单表查询

    ①查询所有     *

    mysql> select * from student;

    ②查询选中字段记录

    mysql> select s_name from student;

    ③条件查询          where

    mysql> select s_name from student where s_id<5;

    ④查询后为字段重命名   as

    mysql> select s_name as 名字 from student;

    ⑤模糊查询     like

    %匹配多个字符

    mysql> select s_name as 姓名 from student where s_name like '李%';

    _匹配一个字符

    mysql> select s_name as 姓名 from student where s_name like '李_';

    mysql> select s_name as 姓名 from student where s_name like '李__';

    ⑥排序(默认升序)  order by  以某个字段为主进行排序

    升序  asc (asc可以不写)

    mysql> select * from student order by sc_id asc;

    降序  desc

    mysql> select * from student order by sc_id desc;

    ⑦限制显示数据数量   limit 

    limit 只接一个数字n时表示显示前面n行

    mysql> select * from student limit 5;

    limit 接两个数字m,n时表示显示第m行之后的n行

    mysql> select * from student limit 2,4;

    ⑧常用聚合函数

    mysql> select * from details;

    最大值  max

    mysql> select max(age) from details;

    最小值 min

    mysql> select min(age) from details;

    求和 sum

    mysql> select sum(age) from details;

    平均值 avg

    mysql> select avg(age) from details;

    四舍五入 round

    mysql> select round(avg(age)) from details;

    统计  count

    mysql> select count(address) from details;

    ⑨分组查询  group by    筛选条件使用having,having后接条件必须是select后存在的字段

    mysql> select age,count(age) from details group by age having age>30;

    以age为组统计每个age的人数最后筛选出age大于30的

    2、子查询   也叫嵌套查询

    mysql> select * from details where age>(select avg(age) from details);

    查询所有age大于平均年龄的信息

    3、关联查询

    ①内连接    inner join

    无条件内连接  又称笛卡尔连接

    mysql> select * from student inner join college;

    有条件内连接  在无条件基础上on接条件

    mysql> select * from student inner join college on sc_id=c_id;

    ②外连接

    左外连接    left join

    以左表为基准,右表没有对应数据以null填充,多余数据去除

    mysql> select * from tb1 left join tb2 on id=t_id;

    mysql> select * from tb2 left join tb1 on id=t_id;

    右外连接   right join

     以右表为基准,左表没有对应数据以null填充,多余数据去除

    mysql> select * from tb1 right join tb2 on id=t_id;

    mysql> select * from tb2 right join tb1 on id=t_id;

     派生表必须命名 as

    mysql> select * from (select * from details where age>30) as a left join student on d_id=s_id;


    ---------------------
    作者:轻风飞落叶
    来源:CNBLOGS
    原文:https://www.cnblogs.com/wangwei13631476567/p/8999429.html
    版权声明:本文为作者原创文章,转载请附上博文链接!
    内容解析By:CSDN,CNBLOG博客文章一键转载插件

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  • 原文地址:https://www.cnblogs.com/admans/p/11722923.html
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