Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one.
Note:
- You must not modify the array (assume the array is read only).
- You must use only constant, O(1) extra space.
- Your runtime complexity should be less than
O(n2)
. - There is only one duplicate number in the array, but it could be repeated more than once.
1 class Solution { 2 public: 3 int findDuplicate(vector<int>& nums) { 4 int fast = 0, slow = 0; 5 do { 6 fast = nums[nums[fast]]; 7 slow = nums[slow]; 8 } while (fast != slow); 9 10 int entry = 0; 11 while (entry != slow) { 12 entry = nums[entry]; 13 slow = nums[slow]; 14 } 15 return entry; 16 } 17 };