python自动化测试之连接几组测试包实例

python自动化测试之连接几组测试包实例

本文实例讲述了python自动化测试之连接几组测试包的方法，分享给大家供大家参考。具体方法如下：

具体代码如下：    
class RomanNumeralConverter(object): 
  def __init__(self): 
    self.digit_map = {"M":1000, "D":500, "C":100, "L":50, "X":10, "V":5, "I":1} 
      
  def convert_to_decimal(self, roman_numeral): 
    val = 0
    for char in roman_numeral: 
      val = self.digit_map[char] 
    return val 
    
import unittest 
class RomanNumeralConverterTest(unittest.TestCase): 
  def setUp(self): 
    self.cvt = RomanNumeralConverter() 
      
  def test_parsing_millenia(self): 
    self.assertEquals(1000, self.cvt.convert_to_decimal("M")) 
      
  def test_parsing_century(self): 
    self.assertEquals(100, self.cvt.convert_to_decimal("C")) 
      
class RomanNumeralConverterCombo(unittest.TestCase): 
  def setUp(self): 
    self.cvt = RomanNumeralConverter() 
      
  def test_multi_millenia(self): 
    self.assertEquals(4000, self.cvt.convert_to_decimal("MMMM")) 
      
  def test_add_up(self): 
    self.assertEquals(2010, self.cvt.convert_to_decimal("MMX")) 
      
if __name__ == "__main__": 
  suite1 = unittest.TestLoader().loadTestsFromTestCase(RomanNumeralConverterTest) 
  suite2 = unittest.TestLoader().loadTestsFromTestCase(RomanNumeralConverterCombo) 
  suite = unittest.TestSuite([suite1, suite2]) 
  unittest.TextTestRunner(verbosity=2).run(suite) 

运行结果如下：    
test_parsing_century (__main__.RomanNumeralConverterTest) ... ok
test_parsing_millenia (__main__.RomanNumeralConverterTest) ... ok
test_add_up (__main__.RomanNumeralConverterCombo) ... ok
test_multi_millenia (__main__.RomanNumeralConverterCombo) ... ok
 
----------------------------------------------------------------------
Ran 4 tests in 0.032s
 
OK

本文实例与前面几篇文章的内容基本一致，只在main中有些不同：
suite1 = unittest.TestLoader().loadTestsFromTestCase(RomanNumeralConverterTest) 
  suite2 = unittest.TestLoader().loadTestsFromTestCase(RomanNumeralConverterCombo) 
  suite = unittest.TestSuite([suite1, suite2]) 
  unittest.TextTestRunner(verbosity=2).run(suite)
希望本文所述对大家的Python程序设计有所帮助。