zoukankan      html  css  js  c++  java
  • 2013成都网络赛 C We Love MOE Girls(水题)

    We Love MOE Girls

    Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
    Total Submission(s): 572    Accepted Submission(s): 378


    Problem Description
    Chikami Nanako is a girl living in many different parallel worlds. In this problem we talk about one of them.
    In this world, Nanako has a special habit. When talking with others, she always ends each sentence with "nanodesu".
    There are two situations:
    If a sentence ends with "desu", she changes "desu" into "nanodesu", e.g. for "iloveyoudesu", she will say "iloveyounanodesu". Otherwise, she just add "nanodesu" to the end of the original sentence.
    Given an original sentence, what will it sound like aften spoken by Nanako?
     
    Input
    The first line has a number T (T <= 1000) , indicating the number of test cases.
    For each test case, the only line contains a string s, which is the original sentence.
    The length of sentence s will not exceed 100, and the sentence contains lowercase letters from a to z only.
     
    Output
    For every case, you should output "Case #t: " at first, without quotes. The t is the case number starting from 1. Then output which Nanako will say.
     
    Sample Input
    2 ohayougozaimasu daijyoubudesu
     
    Sample Output
    Case #1: ohayougozaimasunanodesu Case #2: daijyoubunanodesu
     
    Source


    #include<stdio.h>
    #include<string.h>
    char a[110];
    int main()
    {
    //freopen("250.txt","r",stdin);
        int t,k=1,i;
        scanf("%d",&t);
        while(k<=t)
        {
            scanf("%s",&a);
            printf("Case #%d: ",k);
            int n=strlen(a);
    
            if((a[n-4]-'d'==0)&&(a[n-3]-'e'==0)&&(a[n-2]-'s'==0)&&(a[n-1]-'u'==0))
            {
    
            for(i=0;i<n-4;i++)
            printf("%c",a[i]);
            printf("nanodesu
    ");
    
            }else
            {
                for(i=0;i<n;i++)
                printf("%c",a[i]);
                printf("nanodesu
    ");
            }
            k++;
        }
    }
    View Code
  • 相关阅读:
    mac 配置 iterm2
    python面试题
    待办事项--flask
    八皇后问题c语言版(xcode下通过)
    对分布式一些理解
    观察者模式
    用redis实现悲观锁(后端语言以php为例)
    只用200行Go代码写一个自己的区块链!(转)
    php的生命周期的概述
    linux网络编程1 最简单的socket编程
  • 原文地址:https://www.cnblogs.com/asd1234/p/3394260.html
Copyright © 2011-2022 走看看