zoukankan      html  css  js  c++  java
  • poj1905 Expanding Rods

    精度限定到1e-12即可。

    http://poj.org/problem?id=1905

     1 #include <cstdio>
     2 #include <cmath>
     3 
     4 using namespace std;
     5 
     6 const double pi = 3.14159265359;
     7 const double ep = 1e-12;
     8 
     9 double l, n, c;
    10 
    11 void solve(){
    12     double low = ep, high = pi / 2;
    13     double l1 = (1 + n * c) * l;
    14     double d1, d2, mid;
    15     d2 = l / l1;
    16     while(high - low > ep){
    17         mid = (low + high) / 2;
    18         d1 = sin(mid) / mid;
    19         if(d1 > d2) low = mid;
    20         else high = mid;
    21     }
    22     d1 = sin(low), d2 = sin(low / 2);
    23     printf("%.3f
    ", l * d2 * d2 / d1);
    24 }
    25 
    26 int main(){
    27     //freopen("in.txt", "r", stdin);
    28     while(~scanf("%lf%lf%lf", &l, &n, &c) && (l + 1)){
    29         solve();
    30     }
    31     return 0;
    32 }
    View Code
  • 相关阅读:
    UVA10891
    UVA10453
    UVA 10201
    UVA10154
    UVA11137
    UVA10617
    UVA10271
    UVA10739
    UVA10306
    节流防抖
  • 原文地址:https://www.cnblogs.com/astoninfer/p/4750177.html
Copyright © 2011-2022 走看看