zoukankan      html  css  js  c++  java
  • Linq——Count、Sum、Min、Max、Average

    using System;
    using System.Data;
    using System.Configuration;
    using System.Linq;
    using System.Web;
    using System.Web.Security;
    using System.Web.UI;
    using System.Text;
    using System.Web.UI.WebControls;
    using System.Web.UI.WebControls.WebParts;
    using System.Web.UI.HtmlControls;
    using System.Collections.Generic;
    using System.Collections;
    public partial class _Default : System.Web.UI.Page
    {
        protected void Page_Load(object sender, EventArgs e)
        {
            #region 用Count()得出查询结果的个数
            Response.Write("<hr>用Count()得出查询结果的个数<br>");
            var langCount = (from s in GetStudents()
                               select s.Language)
                               .Distinct()
                               .Count();
            Response.Write(string.Format("<div class='result'>{0}</div>", langCount));
            #endregion
            #region 用Count()的Lambda表达式满足条件的元素个数
            Response.Write("<hr>用Count()得出查询结果的个数<br>");
            var ageCoun = (from s in GetStudents()
                              select s.Age)
                              .Count(a=>a>22);
            Response.Write(string.Format("<div class='result'>{0}</div>", ageCoun));
            #endregion
            #region 用Sum()将查询结果相加
            Response.Write("<hr>用Sum()将查询结果相加<br>");
            var ageSum = (from s in GetStudents()
                          select s.Age)
                           .Sum();
            //var ageSum = GetStudents().Sum(s=>s.Age);
            Response.Write(string.Format("<div class='result'>{0}</div>", ageSum));
            #endregion
            #region 用Min()得出查询结果的最小值
            Response.Write("<hr>用Min()得出查询结果的最小值<br>");
            var ageMin = (from s in GetStudents()
                          select s.Age)
                           .Min();
            //var ageMin = GetStudents().Min(s => s.Age);
            Response.Write(string.Format("<div class='result'>{0}</div>", ageMin));
            #endregion
            #region 用Max()得出查询结果的最大值
            Response.Write("<hr>用Max()得出查询结果的最大值<br>");
            var ageMax = (from s in GetStudents()
                          select s.Age)
                           .Max();
            //var ageMax = GetStudents().Max(s => s.Age);
            Response.Write(string.Format("<div class='result'>{0}</div>", ageMax));
            #endregion
            #region 用Average()得出查询结果的平均值
            Response.Write("<hr>用Average()得出查询结果的平均值<br>");
            var ageAverage = (from s in GetStudents()
                          select s.Age)
                          .Average();
            //var ageAverage = GetStudents().Average(s => s.Age);
            Response.Write(string.Format("<div class='result'>{0}</div>", ageAverage));
            #endregion
        }
        #region 构造一个学生集合体
        private List<Student> GetStudents()
        {
            List<Student> students = new List<Student> {
                 new Student{ Name="YOUNG", Age=25, Language="Chinese"},
                 new Student{ Name="JESSIE", Age=21, Language="Scotland"},
                 new Student{ Name="KELLY", Age=18, Language="English"},
                 new Student{ Name="JUNE", Age=20, Language="English"},
                 new Student{ Name="ADRIAN", Age=22, Language="Italy"},
                 new Student{ Name="BRUCE", Age=17, Language="Scotland"},
                 new Student{ Name="BRANT", Age=30, Language="Germany"},
                 new Student{ Name="BEN", Age=25, Language="Chinese"}
            };
            return students;
        }
        #endregion
    }
    #region 学生类
    class Student
    {
        public int Age { get; set; }
        public string Name { get; set; }
        public string Language { get; set; }
    }
    #endregion

    转自:http://blog.sina.com.cn/s/blog_5421dfd20100i6cw.html

  • 相关阅读:
    最小费用最大流问题
    成大事必备9种能力、9种手段、9种心态
    转 fpga学习经验2
    算法 FFT理论1
    FPGA进阶之路1
    FPGA:亲和力激活竞争力
    1030 又回来了
    转 fpga学习经验1
    调查:近半大学生愿接受15002000元月薪
    转 观点:哪些人适合做FPGA开发(精华)
  • 原文地址:https://www.cnblogs.com/axu92312/p/5938166.html
Copyright © 2011-2022 走看看