1、题目描述
请判断一个链表是否为回文链表。
示例 1:
输入: 1->2 输出: false
示例 2:
输入: 1->2->2->1 输出: true
进阶:
你能否用 O(n) 时间复杂度和 O(1) 空间复杂度解决此题?
2、题解
2.1、解法一
# Definition for singly-linked list.
# class ListNode(object):
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution(object):
def get_elem(self,head):
n = head
ret = []
while n:
ret.append(n.val)
n = n.next
return ret
def isPalindrome(self, head):
"""
:type head: ListNode
:rtype: bool
"""
ret = self.get_elem(head)
if len(ret) == 0 or len(ret) == 1:
return True
mid = len(ret)//2
if len(ret)%2 == 0:
left = ret[:mid]
right = ret[mid:]
right.reverse()
else:
left = ret[:mid]
right = ret[mid+1:]
right.reverse()
if left == right:
return True
return False