用力戳我下载全套题的pdf~
用力戳我直达cf评测系统~
目前已做出:
Problem A. Number Theory Problem
Problem D. Ice Cream Tower
Problem L. World Cup
题解:
A。简单数论
|
1
2
3
4
5
6
7
8
9
10
11
12
|
#include <bits/stdc++.h>using namespace std;int main(){ int t, n, Case; scanf("%d",&t); for(Case = 1; Case <= t; Case++) { scanf("%d",&n); printf("Case #%d: %d
",Case, n / 3); }} |
D。二分 + 贪心
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
|
#include <bits/stdc++.h>typedef long long ll;using namespace std;ll a[300030];ll tp[300030];//judge时用int t, n ,k;bool judge(int x){ memset(tp,-1,sizeof(tp)); for(int i = 0; i < x; i++) tp[i] = a[i]; int pos = x; for(int i = 2; i <= k; i++) //层数 { for(int j = 0; j < x; j++) //每一层有 x 个 { pos = lower_bound(a + pos, a + n, tp[j] * 2) - a; if(pos + 1 > n) return false; tp[j] = a[pos]; //更新当前最底层 pos++; //下一次 从 下一个数开始搜 } } return true; //叠加成功则返回true}int main(){ int Case; scanf("%d",&t); for(Case = 1; Case <= t; Case++) { memset(a,0,sizeof(a)); scanf("%d%d",&n, &k); for(int i = 0; i < n; i++) scanf("%I64d",a + i); sort(a, a + n); int low = 0, high = n / k, mid; while(low < high) { int mid = (low + high + 1) >> 1; if(judge(mid)) low = mid; //搜右界 else high = mid - 1; } printf("Case #%d: %d
",Case, low); }} |
L。模拟
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
|
#include <bits/stdc++.h>#define MEM(a,b) memset(a,b,sizeof(a))using namespace std;int sco[12][12][12][12];void init(){ MEM(sco,0); int op1[]={3,1,0}; // a a a b b c int op2[]={0,1,3}; // b c d c d d //枚举六场比赛 for(int k1 = 0; k1 <= 2; k1++) for(int k2 = 0; k2 <= 2; k2++) for(int k3 = 0; k3 <= 2; k3++) for(int k4 = 0; k4 <= 2; k4++) for(int k5 = 0; k5 <= 2; k5++) for(int k6 = 0; k6 <= 2; k6++) { //根据op1 op2的注释统计分值 int A = op1[k1] + op1[k2] + op1[k3]; int B = op2[k1] + op1[k4] + op1[k5]; int C = op2[k2] + op2[k4] + op1[k6]; int D = op2[k3] + op2[k5] + op2[k6]; sco[A][B][C][D] ++; //累计最终榜单 }}int main(){ int n, a, b, c, d; init(); //只需要暴力跑一次就行 scanf("%d",&n); for(int Case = 1; Case <= n; Case++) { scanf("%d%d%d%d",&a, &b, &c, &d); if(sco[a][b][c][d] == 0) printf("Case #%d: Wrong Scoreboard
",Case); else if(sco[a][b][c][d] == 1) printf("Case #%d: Yes
",Case); else printf("Case #%d: No
",Case); }} |