A == B ?
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 64239 Accepted Submission(s): 10060
Problem Description
Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".
Input
each test case contains two numbers A and B.
Output
for each case, if A is equal to B, you should print "YES", or print "NO".
Sample Input
1 2 2 2 3 3 4 3
Sample Output
NO YES YES NO/*第一次做总是将题目理解的过于简单。看过讨论区后 才知道要考虑非常多种情况,对于这道题的hdoj仅仅须要去掉 小数点后无意义的0就能够AC,而不须要考虑整数部分无意义 的0。不知道为啥。 */ #include<stdio.h> #include<string.h> char a[40000],b[40000]; void pop(char *s) //去掉字符串小数部分没有意义的0。 { int i,len=strlen(s)-1; for(i=len;i>=0;i--) { if(s[i]=='0') len--; else break; } if(s[i]=='.')//假设像9.00这种数。小数点则也须要去掉。 len--; s[len+1]='