zoukankan      html  css  js  c++  java
  • 列表、字典的增删改查

    一、列表:

    # 列表的作用:存多个值,可以修改
    # hobby = ['play','eat','sleep']
    #
    # 列表的具体操作
    # 查看:
    # hobby = ['play','eat','sleep',['egon','ysb']]
    # f = hobby[2]  # 查看hobbyt列表内第二个元素
    # print(f)
    #
    # 增加(1):
    # hobby = ['play','eat','sleep',['egon','ysb']]
    # hobby.append(元素)
    # f = hobby.append('chenyang')
    # print(f)
    #
    # 增加(2)
    # hobby = ['play','eat','sleep',['egon','ysb']]
    # hobby.insert(0,amy)
    # print(hobby)
    #
    # 删除(1):
    # hobby = ['play','eat','sleep',['egon','ysb']]
    # X = hobby.pop(1)    #1为需要删除的字符,pop元素可以弹出需要删除的元素
    # print(x)
    # print(hobby)
    #
    # 删除(2):
    # hobby = ['play','eat','sleep',['egon','ysb']]
    # X = hobby.remove(1)    #1为需要删除的字符,remove为直接删除,无法保留
    # print(x)
    # print(hobby)
    #
    # 改:
    # hobby = ['play','eat','sleep',['egon','ysb']]
    # hobby[0]=1    #0代表列表内的索引,1为需要更改的字符
    # print(hobby)
    #

    二、字典

    #
    # 字典的作用:key是唯一的,可以存储多个值
    # 字典的具体操作
    # 查:
    # dic1 = {'name':'chenyang','age':38,'sex':'male'}
    # f = dic1['name']  # 查看hobbyt列表内第一个元素,通过key查找到value
    # print(f)
    #
    # 取:通过key找到value。
    # dic1 = {'name':'chenyang','age':38,'sex':'male'}
    # print(dic1.get('name',None))    #通过key取到value,如果找不到则返回None
    #
    # 存:字典内有相应的key就覆盖原来的value,反之新增key、value
    # dic1 = {'name':'chenyang','age':38,'sex':'male'}
    # dic1['sex'] = 'female'
    # dic1['hobby'] = 'male'
    # print(dic1)
    #
    # 改:
    # dic1 = {'name':'chenyang','age':38,'sex':'male'}
    # dic1.update({'hobby':male,'sex':'female'})
    # print(dic1)
    #
    # 长度:计算字典内所有字典的长度
    # dic1 = {'name':'chenyang','age':38,'sex':'male'}
    # print(len(dic1))
    #
    # 包含:查找字典内的key
    # dic1 = {'name':'chenyang','age':38,'sex':'male'}
    # print('name' in dic1)
    #
    # 输出所有的key和value
    # dic1 = {'name':'chenyang','age':38,'sex':'male'}
    # print(dic1.items)
    #  for k in dic1:
    #       print(k,dic1[k])
    #      print(k)
    #
    # 方法2
    # for k in dic1:
    # print(k,dic1[k])
    #
    # 输出所有的key
    # dic1 = {'name':'chenyang','age':38,'sex':'male'}
    # print(dic1.key)
    #
    # 输出所有的value
    # dic1 = {'name':'chenyang','age':38,'sex':'male'}
    # print(dic1.value)
  • 相关阅读:
    nexus3.x Liunx私库安装教程 (亲测有用)
    nexus 3.x下载 3.18.1(maven 私服)
    halo项目源码本地部署解决方案
    gradle的安装配置
    raw.githubusercontent.com 访问不了
    springboot使用quartz解决调用不到spring注入service的问题
    Linux在不能使用yum的环境下安装pgsql(公司内网)
    idea 里面的maven依赖下载不了,以及mabtis依赖包错误
    关于oracle 数据库效率的优化
    关于oracle 不常用的job 运行时间设置
  • 原文地址:https://www.cnblogs.com/bingpan/p/7258904.html
Copyright © 2011-2022 走看看