循环-10. 求序列前N项和*

/*
 * Main.c
 * C10-循环-10. 求序列前N项和
 *  Created on: 2014年7月30日
 *      Author: Boomkeeper
 *******部分通过*******
 */

#include <stdio.h>

int main(void) {

    double sum = 0.0; //记录前N项和
    int numerator = 2,denominator = 1; //分子分母
    int N; //题目中的N
    int i;//循环使用
    int tem = 0;

    scanf("%d", &N);

    if (N == 1)
        printf("%.2f
", (double) numerator / denominator);
    else {
        sum = (double) numerator / denominator;
        for (i = N; i > 1; i--) {
            tem = denominator;
            denominator = numerator;
            numerator = numerator + tem;
            sum += (double) numerator / denominator;
        }
        printf("%.2f
", sum);
    }

    return 0;
}

不完美...

题目链接：

http://pat.zju.edu.cn/contests/basic-programming/%E5%BE%AA%E7%8E%AF-10

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