1 /* 2 * Main.c 3 * C18-循环-18. 龟兔赛跑 4 * Created on: 2014年8月4日 5 * Author: Boomkeeper 6 ******部分通过******* 7 */ 8 9 #include <stdio.h> 10 #include <stdlib.h> 11 12 int t = 0; 13 int distanceR = 0, distanceT = 0; 14 //int *pdistanceR = &distanceR, *pdistanceT = &distanceT; 15 16 void competition() { 17 18 //兔子的控制器，如果flag=0，可以继续跑并且比较与乌龟的距离，否则直至count满30才可以继续 19 int flag = 0, count = 0; 20 int i; 21 for (i = 1; i <= t; i++) { 22 23 distanceT += 3; 24 25 if (flag == 0) { 26 27 distanceR += 9; 28 29 //每10分钟兔子回头看，如果超过乌龟就休息30分钟，否则继续跑10分钟 30 if (i % 10 == 0) { 31 if (distanceR > distanceT) 32 flag = 1; 33 else 34 continue; 35 } 36 } 37 38 if (flag == 1) { 39 count++; 40 if (count == 30){ 41 flag = 0; 42 count = 0; 43 } 44 45 } 46 47 } 48 } 49 50 int main(void) { 51 52 scanf("%d", &t); 53 competition(); 54 if (distanceR > distanceT) 55 printf("^_^ %d ", distanceR); 56 if (distanceR < distanceT) 57 printf("@_@ %d ", distanceT); 58 if (distanceR == distanceT) 59 printf("-_- %d ", distanceR); 60 return 0; 61 }
题目链接：
http://pat.zju.edu.cn/contests/basic-programming/%E5%BE%AA%E7%8E%AF-18
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