CF76A.Gift
题意:noi2014魔法森林弱化版QwQ,最小化(max(g_i)*G + max(s_i)*S)的最小生成树
考虑按g升序加边,用已在生成树中的边和新加入的边求当前最小生成树。
复杂度(O(nm))
vector真好用
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstring>
#include <vector>
using namespace std;
typedef long long ll;
const int N = 205, M = 50005;
const ll inf = 2e18+5;
inline int read() {
int x = 0, f = 1; char c = getchar();
while(c<'0' || c>'9') {if(c=='-') f=-1; c=getchar();}
while(c>='0' && c<='9') {x=x*10+c-'0'; c=getchar();}
return x*f;
}
int n, m, G, S;
struct edge {
int x, y, g, s;
bool operator <(const edge &r) const {
return g < r.g;
}
} e[M];
bool cmp_s(const edge &a, const edge &b) {
return a.s < b.s;
}
int fa[N];
int find(int x) {return x == fa[x] ? x : fa[x] = find(fa[x]);}
vector<edge> v;
vector<edge>::iterator it;
ll ans = inf;
ll kruskal(int m) { //printf("kruskal %d
", m);
int mg = 0, ms = 0;
for(int i=1; i<=n; i++) fa[i] = i;
int cnt = 0;
for(it = v.begin(); it != v.end(); ) {
int x = find(it->x), y = find(it->y);
//printf("%d %d %d %d
", e[i].x, e[i].y, x, y); cout << endl;
if(x == y) {
it = v.erase(it);
continue;
}
fa[y] = x;
mg = max(mg, it->g);
ms = max(ms, it->s);
if(++cnt == n-1) break;
it++;
}
if(cnt == n-1) return (ll) mg * G + (ll) ms * S;
else return inf;
}
void solve() {
sort(e+1, e+1+m);
for(int i=1; i<=n-2; i++) v.push_back(e[i]);
sort(v.begin(), v.end(), cmp_s);
for(int p=n-1; p<=m; p++) { //printf("ppp %d
", p);
edge now = e[p];
int flag = 0;
for(it = v.begin(); it != v.end(); it++) {
if(it->s > now.s) {
v.insert(it, now);
flag = 1;
break;
}
}
if(!flag) v.insert(it, now);
ans = min(ans, kruskal(p));
}
if(ans == inf) ans = -1;
cout << ans;
}
int main() {
//freopen("in", "r", stdin);
cin >> n >> m >> G >> S;;
for(int i=1; i<=m; i++) {
e[i].x = read();
e[i].y = read();
e[i].g = read();
e[i].s = read();
}
solve();
}