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  • 【Luogu】P2173网络(LCT)

      题目链接

      这次坑我的是与或的结合顺序……

      开十个LCT记录一下即可。以上。

      

    #include<cstdio>
    #include<cstring>
    #include<cstdlib>
    #include<algorithm>
    #include<cctype>
    #include<map>
    #define maxn 210050
    #define maxc 12
    using namespace std;
    inline long long read(){
        long long num=0,f=1;
        char ch=getchar();
        while(!isdigit(ch)){
            if(ch=='-')    f=-1;
            ch=getchar();
        }
        while(isdigit(ch)){
            num=num*10+ch-'0';
            ch=getchar();
        }
        return num*f;
    }
    
    
    
    struct Splay{
        struct Node{
            int e[2],fa,val,maxi,tag;
        }tree[maxn];
        inline int iden(int x){    return x==tree[tree[x].fa].e[1];    }
        inline void connect(int x,int fa,int how){    tree[x].fa=fa;    tree[fa].e[how]=x;    }
        inline bool isroot(int x){    return x!=tree[tree[x].fa].e[0]&&x!=tree[tree[x].fa].e[1];    }
        inline void update(int x){    tree[x].maxi=max(tree[x].val,max(tree[tree[x].e[0]].maxi,tree[tree[x].e[1]].maxi));    }
        void reverse(int x){
            swap(tree[x].e[0],tree[x].e[1]);
            tree[x].tag^=1;
        }
        void pushdown(int x){
            if(tree[x].tag==0)    return;
            tree[x].tag=0;
            if(tree[x].e[0])    reverse(tree[x].e[0]);
            if(tree[x].e[1])    reverse(tree[x].e[1]);
        }
        void rotate(int x){
            int y=tree[x].fa;    int r=tree[y].fa;
            int sony=iden(x);    int sonr=iden(y);
            tree[x].fa=r;    if(!isroot(y))    tree[r].e[sonr]=x;
            int b=tree[x].e[sony^1];
            connect(b,y,sony);
            connect(y,x,sony^1);
            update(y);
        }
        inline void pushto(int x){
            if(!isroot(x))    pushto(tree[x].fa);
            pushdown(x);
            return;
        }
        void splay(int x){
            pushto(x);
            while(!isroot(x)){
                int fa=tree[x].fa;
                if(!isroot(fa))
                    if(iden(fa)==iden(x))    rotate(fa);
                    else                    rotate(x);
                rotate(x);
            }
            update(x);
        }
        inline void access(int x){
            int last=0;
            while(x){
                splay(x);
                tree[x].e[1]=last;
                update(x);
                last=x;    x=tree[x].fa;
            }
        }
        inline void makeroot(int x){
            access(x);
            splay(x);
            reverse(x);
        }
        inline int findroot(int x){
            access(x);
            splay(x);
            while(tree[x].e[0])    x=tree[x].e[0];
            return x;
        }
        inline void split(int x,int y){
            makeroot(x);
            access(y);
            splay(y);
        }
        inline void link(int x,int y){
            split(x,y);
            tree[x].fa=y;
        }
        inline void cut(int x,int y){
            split(x,y);
            if(tree[y].e[0]!=x||tree[x].e[1])    return;
            tree[x].fa=tree[y].e[0]=0;
        }
    }s[maxc];
    
    inline long long calc(long long x,long long y,long long n){    return x*n+y;    }
    map<long long,int>d;
    
    int old[maxn];
    int sum[maxn][maxc];
    
    int main(){
        int n=read(),m=read(),c=read(),e=read();
        for(int i=1;i<=n;++i){
            int x=read();
            for(int j=0;j<=c;++j)    s[j].tree[i].val=s[j].tree[i].maxi=x;
        }
        for(int i=1;i<=m;++i){
            int from=read(),to=read(),col=read();
            sum[from][col]++;    sum[to][col]++;
            old[i+n]=col;
            if(from>to)    swap(from,to);
            d[calc(from,to,n)]=i+n;
            s[col].link(from,i+n);
            s[col].link(to,i+n);
        }
        for(int i=1;i<=e;++i){
            int opt=read();
            if(opt==0){
                int x=read(),y=read();
                for(int j=0;j<=c;++j){
                    s[j].splay(x);
                    s[j].tree[x].val=y;
                    s[j].update(x);
                }
            }
            else if(opt==1){
                int from=read(),to=read(),col=read();
                if(from>to)    swap(from,to);
                if(d.count(calc(from,to,n))==0){
                    printf("No such edge.
    ");
                    continue;
                }
                int id=d[calc(from,to,n)];
                if(col==old[id]){
                    printf("Success.
    ");
                    continue;
                }
                if(sum[from][col]==2||sum[to][col]==2){
                    printf("Error 1.
    ");
                    continue;
                }
                if(s[col].findroot(from)==s[col].findroot(to)){
                    printf("Error 2.
    ");
                    continue;
                }
                sum[from][old[id]]--;    sum[to][old[id]]--;
                sum[from][col]++;        sum[to][col]++;
                s[old[id]].cut(from,id);
                s[old[id]].cut(to,id);
                old[id]=col;
                s[old[id]].link(from,id);
                s[old[id]].link(to,id);
                printf("Success.
    ");
            }
            else{
                int col=read(),x=read(),y=read();
                if(s[col].findroot(x)!=s[col].findroot(y)){
                    printf("-1
    ");
                    continue;
                }
                s[col].split(x,y);
                //printf("%d %d>>>
    ",y,s[col].tree[y].val);
                printf("%d
    ",s[col].tree[y].maxi);
            }
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/cellular-automaton/p/8871667.html
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