Given a positive integer num, write a function which returns True if num is a perfect square else False.
Note: Do not use any built-in library function such as sqrt.
Example 1:
Input: 16
Returns: True
Example 2:
Input: 14
Returns: False
//连续的奇数之和即为平方数
class Solution {
public:
bool isPerfectSquare(int num) {
for(int i=1;num>0;i+=2)
{
num -= i;
}
return num==0;
}
};