全栈试卷二

# 第三次作业讲解：

#2.根据范围获取其中3和7整除的所有数的和，并返回调用者
#符合条件的数字个数以及符合条件的数字的总数和
def func(start,end):
    n=[]
    sum=0
    for i in range(start,end):
        if i % 3 == 0 and i % 7 == 0:
            n.append(i)
            sum+=i
    print(len(n))
    print('总数和是 %d' %sum)
func(1,100)

#8、使用 set 集合获取两个列表 l1 = [11, 22, 33], l2 = [22, 33, 44] 中相同的元素集合
l1 = [11, 22, 33]
l2 = [22, 33, 44]
same=set(l1)&set(l2)
print(same)
#9、定义函数统计一个字符串中大写字母、小写字母、数字的个数，并以字典为结果返回给调用者
def num(ret):
    yy={'大写':0,'小写':0,'数字':0}
    for i in ret:
        i = str(i)
        if i.isupper():
            yy['大写']+=1
        elif i.islower():
            yy['小写']+=1
        elif i.isdecimal():
            yy['数字']+=1
    return yy
ret=input('>>>')
print(num(ret)

#11、检查代码，如有错误请改正(禁止运行代码):
# #a.
def func(x,y,z):
    print(x,y,z)
func(1,2,3)
# # 输出结果为:123
# #
# # b.
def func(x,z,y=5):
      print(x,y,z)
func(1,3,3)
# # 输出结果为:133
# #
# # c.
def func(x,y,*z):
   print(x,y,z)
func(1,2,3,4,5,6)
# # 输出结果为:12(3,4,5,6)
# #
# # d.
def func(x,y,*z):
   print(x,y,z)
func(1,2,3,4,5,6,6)
# # 输出结果为:1 2(3,4,5,6,6)
# #
# # e.
def func(x,*z,**y):
   print(x,y,z)
func(1,2,3)
# # 输出结果为:1{}(2,3)
# #
# # f.
def func(x,*y,**z):
   print(x,y,z)
func(1,name=2,age=3)
# # 输出结果为:1（）{"name":2,"age":3}
# #
# # g.
def func(x,*y,**z):
   print(x,y,z)
func(1,2,3,4, name=2,age=3)
# # 输出结果为:1(2,3,4){"name":2,"age":3}
# #
# # h.
def func(x=2,*y,**z):
   print(x,y,z)
func(name=2,age=3)
# # 输出结果为:2(){'name':2,'age':3}
# 13、书写输出结果(禁止运行代码):
# a.
def func(*y,**z):
   print(y,z)
func(1,2,3,4,5)
# # 输出结果为:(1,2,3,4,5){}
# #
# #
# # b.
def func(*y,**z):
   print(y,z)
func([1,2,3,4,5])
# # 输出结果为:([1,2,3,4,5]){}
# #
# # c.
def func(*y,**z):
   print(y,z)
func(*[1,2,3,4,5])
# # 输出结果为:(1,2,3,4,5){}
# #
# # d.
def func(*y,**z):
   print(y,z)
func(*[1,2,3,4,5],name="alex",age=19)
# # 输出结果为:(1,2,3,4,5){"name":"alex","age":19}
# #
# # e.
def func(*y,**z):
   print(y,z)
func(*[1,2,3,4,5], { "name":"alex","age":19})
# # 输出结果为:(1,2,3,4,5,{ "name":"alex","age":19}){}
# #
# # f.
def func(*y,**z):
   print(y,z)
func(*[1,2,3,4,5], **{ "name":"alex","age":19})
# # 输出结果为:(1,2,3,4,5){ "name":"alex","age":19}
# 14、书写执行结果(禁止运行代码)
def func1(x=1,*y,**z):
   print(x,y,z)
   return y  #结束的标志
   print(x)
def func2(arg):
   ret = func1(name=arg)
   print(ret)
result = func2("Fuck")
print(result)
# 输出结果为:1(){"name":"fuck"}  ()     None
# 15、书写执行结果(禁止运行代码)
def func(arg):
   arg.append(55)
li = [11, 22, 33, 44]
func(li)
print(li)
li = func(li)
print(li)
# 输出结果为:[11, 22, 33, 44,55]    None
# 16、书写执行结果(禁止运行代码)
def f1(arg):
   print(arg+100)
def f2(arg):
   ret = f1(arg+1)
   print(arg)
   print(ret)
ret = f2(7)
print(ret)
# 输出结果为:108   7   None
# 17、简述 Python3 中的 range 函数和 Python2.7 中的 range 函数有什么区别
# 3.x range 不会生成值   只有用的时候才会生成  封装成函数  迭代器
# 2.7 range 会直接生成一个列表，值已经生成
#
# 18、书写执行结果(禁止运行代码)
a = "oldboy %"
print(a)
# # 输出结果为:oldboy %
b = "oldboy %d %%" % (12,)
print(b)
# 输出结果为:oldboy 12%
# 20、书写执行结果(禁止运行代码)
def func(a1):
   return a1 + 100
func = lambda a1: a1 + 200
ret = func(10)
print(ret)
# 输出结果为:210  #函数覆盖
#23、将字符串 "老男人" 转换成 UTF-8 编码的字节类型
name='老男人'
print(bytes(name,encoding='utf-8'))
print(name.encode('utf-8'))

#24、利用内置函数将十进制数字 12，分别转换成 二进制、八进制、十六进制 表示的字符串
print(bin(12))
print(oct(12))
print(hex(12))

# 26、利用内置函数 zip()，实现功能
l1 = ["alex",22,33,44,55]
l2 = ["is",22,33,44,55]
l3 = ["good",22,33,44,55]
l4 = ["guy",22,33,44,55]
# # 请获取字符串 s = "alex_is_good_guy"
print('_'.join((list(zip(l1,l2,l3,l4))[0])))

# 27、判断输出结果是否相同?并可得到什么结论?
def f1(arg):
   print(id(arg))
n = 1111111
print(id(n))
f1(n)
# 输出的两个值是否相同:   相同
# 执行函数是调用变量值不是复制
#
# 28、书写执行结果(禁止运行代码)
# a.
NAMELIST = ["alex", "eric"]
def func():
   NAMELIST = 123
func()
print(NAMELIST)
# 输出结果为:["alex", "eric"]
# b.
NAMELIST = ["alex", "eric"]
def func():
   global NAMELIST
   NAMELIST = 123
func()
print(NAMELIST)
# 输出结果为:123
# c.
NAMELIST = ["alex", "eric"]
def func():
   NAMELIST.append("seven")
func()
print(NAMELIST)
# 输出结果为:["alex", "eric","seven"]
# d.
NAMELIST = ["alex", "eric"]
def func():
   NAMELIST = 123
   global NAMELIST
func()
print(NAMELIST)
# 输出结果为:["alex", "eric"]
# 29、书写执行结果(禁止运行代码)
# a.
name = "root"
def func():
   name = "seven"
   def outer():
       name = "eric"
       def inner():
           global name
           name = "蒙逼了吧..."
       print(name)
   print(name)
ret = func()
print(ret)
print(name)
# 输出结果为:seven   None root
# b.
name = "root"
def func():
   name = "seven"
   def outer():
       name = "eric"
       def inner():
           global name
           name = "蒙逼了吧..."
       print(name)
   o = outer()
   print(o)
   print(name)
ret = func()
print(ret)
print(name)
# 输出结果为:eric  None   seven   None root
# c.
name = "root"
def func():
   name = "seven"
   def outer():
       name = "eric"
       def inner():
               global name
               name = "    ..."
       print(name)
       inner()
   o = outer()
   print(o)
   print(name)
ret = func()
print(ret)
print(name)
# 输出结果为:eric    None   seven   None       ...
# d.
name = "root"
   def func():
       name = "seven"
       def outer():
           name = "eric"
           def inner():
               nonlocal name
               name = "蒙逼了吧..."
               print(name)
           inner()
        o = outer()
        print(o)
        print(name)
ret = func()
print(ret)
print(name)
# 输出结果为:
# 30、书写执行结果并解释每一步操作
# a.
name = "苍老师"
def outer(func):
   name = 'alex'
   func() #结果，就是执行的show
def show():
   print(name)
outer(show)
# 结果：苍老师
#
#
# b.
name = "苍老师"
def outer():
   name = "波多"
   def inner():
       print(name)
   return inner()
ret = outer()
print(ret)
# 输出结果为:波多 None
# c.
name = "苍老师"
def outer():
   name = "波多"
   def inner():
       print(name)
   return inner
ret = outer()
ret()
print(ret)
result = ret()
print(result)
# 输出结果为:波多  inne的内存地址  None
#
#
# d.
name = "苍老师"
def outer():
   name = "波多"
   def inner():
       print(name)
   return inner  #返回内存地址
ret = outer()
print(ret)
result = ret()#执行inner函数，打印波多
print(result)#inner无返回值 打印的是None
# 输出结果为:inner的内存地址  波多   None
#
# e.
name = "苍老师"
def outer(func):
   def inner():
       name = "李杰"
       func()
   return inner
def show():
   print(name)#打印全局的
outer(show)()
# 输出结果为:苍老师
#
# 31、书写执行结果并解释每一步操作
#a.
def outer(func,z,y):
   func(z)
def show(x):
   return x * x
ret = outer(show,9,23)
print(ret)
# 输出结果为:None
#
# # c.
def outer(func,z,y):
   return func(z)
def show(x):
   return x * x
ret = outer(show,9,23)
print(ret)
# 输出结果为:81
#
def outer(func,z,y):
   func(z,y)
f1 = lambda x,y: x + y
ret = outer(f1,11,23)
print(ret)
# 输出结果为:None
#
# d.
def outer(func,z,y):
   return func(z,y)
f1 = lambda x,y: x + y
ret = outer(f1,11,23)
print(ret)
# 输出结果为:34
#
# 32、写输出结果
# a.
def f5(arg):
   arg.append('偷到 500 万')
def f4(arg):
   arg.append('开第四个门')
   f5(arg)
   arg.append('关第四个门')
def f3(arg):
   arg.append('开第三个门')
   f4(arg)
   arg.append('关第三个门')
def f2(arg):
   arg.append('开第二个门')
   f3(arg)
   arg.append('关第二个门')
def f1(arg):
   arg.append('开一个门')
   f2(arg)
   arg.append('关一个门')
user_list = []
result = f1(user_list)
print(user_list)
print(result)
# # 输出结果为:['开一个门','开第二个门','开第三个门','开第四个门''偷到 500 万','关第四个门','关第三个门','关第二个门','关一个门']   None
# #
# # b.
def f5(arg):
   arg = arg + 5
def f4(arg):
   arg = arg + 4
   f5(arg)
   arg = arg + 4
def f3(arg):
   arg = arg + 3
   f4(arg)
   arg = arg + 3
def f2(arg):
   arg = arg + 2
   f3(arg)
   arg = arg + 2
def f1(arg):
   arg = arg + 1
   f2(arg)
   arg = arg + 1
num = 1
result = f1(num)
print(num)
print(result)
# 输出结果为:1 None
#
# c.
def f5(arg):
   arg = arg + 5
   return arg
def f4(arg):
   arg = arg + 4
   f5(arg)
   arg = arg + 4
   return arg
def f3(arg):
   arg = arg + 3
   f4(arg)
   arg = arg + 3
   return arg
def f2(arg):
   arg = arg + 2
   f3(arg)
   arg = arg + 2
   return arg
def f1(arg):
   arg = arg + 1
   f2(arg)        #  执行完f2(arg)  因为无法返回则为3
   arg = arg + 1
   return arg
num = 1
result = f1(num)
print(num)
print(result)
# 输出结果为
#33、利用递归实现 1*2*3*4*5*6*7=5040
#法一：
from functools import reduce
res=reduce(lambda x,y:x*y,[x for x in range(1,8)])
print(res)
#法二：
def func(x,y):
   y *= x
   x += 1
   if x == 8:
      return y
   return  func(x,y)
res=func(2,1)
print(res)
# 34 a. 利用 filter、自定义函数 获取 l1 中元素大于 33 的所有元素 l1 = [11, 22, 33, 44, 55]
l1 = [11, 22, 33, 44, 55]
res=filter(lambda x:x > 33,l1)
print(list(res))
# b.利用 filter、lambda 表达式 获取 l1 中元素小于 33 的所有元素 l1 = [11, 22, 33, 44, 55]
l1 = [11, 22, 33, 44, 55]
res=filter(lambda x:x < 33,l1)
print(list(res))
# c.利用 map、自定义函数 将所有是奇数的元素加 100 l1 = [11, 22, 33, 44, 55]
l1 = [11, 22, 33, 44, 55]
def jsj(i):
   if i % 2 ==1:
      i = i + 100
      return i
   else:
      return i
print(list(map(jsj,l1)))
# d.利用 map、lambda 表达式 将所有是偶数的元素加 100 l1 = [11, 22, 33, 44, 55]
l1 = [11, 22, 33, 44, 55]
res=map(lambda i:i+100 if i%2==0 else i,l1)
print(list(res))

#36、第一个列表中的数字无序不重复排列，第二个列表为空列表
# 需求:
# 取出第一个列表的最小值 放到第二个列表的首个位置，
# 取出第一个列表的最小值(仅大于上一次的最小值) 放到第二个列表的首个位置，
# 取出第一个列表的最小值(仅大于上一次的最小值) 放到第二个列表的首个位置， ...
# 依此类推，从而获取一个有序的列表 l2，并将其返回给函数调用者。
l1 = [1,5,4,6,8,3,2,9,0]
l2 = []
def func(la,lb):
    if len(la) ==0:
        return lb
    lb.insert(0,la.pop(la.index(min(la))))
    ret = func(la,lb)
    return ret
func(l1,l2)
print(l2)
#37、猴子第一天摘下若干个桃子，当即吃了一半，还不过瘾就多吃了一个。第二天早上又将剩下的桃子吃了一半，
# 还是不过瘾又多吃 了一个。以后每天都吃前一天剩下的一半再加一个。到第 10 天刚好剩一个。
# 问猴子第一天摘了多少个桃子?1534

n = 1
func =lambda x:(x+1)*2
for i in range(9):
   n =func(n)
print(n)