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  • mysql中json_remove函数的使用?

    需求描述:

      今天看json记录,可以通过json_remove函数对一个key或多个key从个json记录中去掉.

    操作过程:

    1.查看一个已经存在的json表

    mysql> select * from tab_json;
    +----+---------------------------------------------------------------------------------------+
    | id | data                                                                                  |
    +----+---------------------------------------------------------------------------------------+
    |  1 | {"age": 54, "tel": 15046464563, "passcode": "654567"}                                 |
    |  2 | {"age": "33", "tel": 189776542, "name": "David", "olds": "12", "address": "Hangzhou"} |
    +----+---------------------------------------------------------------------------------------+
    2 rows in set (0.00 sec)

    2.通过json_remove函数,将json记录中的key去掉

    mysql> select json_remove(data,'$.age') from tab_json;  #查询时,去掉某些的key
    +--------------------------------------------------------------------------+
    | json_remove(data,'$.age')                                                |
    +--------------------------------------------------------------------------+
    | {"tel": 15046464563, "passcode": "654567"}                               |
    | {"tel": 189776542, "name": "David", "olds": "12", "address": "Hangzhou"} |
    +--------------------------------------------------------------------------+
    2 rows in set (0.00 sec)
    
    mysql> select json_remove(data,'$.age','$.name') from tab_json; #查询时,去掉某些的key
    +---------------------------------------------------------+
    | json_remove(data,'$.age','$.name')                      |
    +---------------------------------------------------------+
    | {"tel": 15046464563, "passcode": "654567"}              |
    | {"tel": 189776542, "olds": "12", "address": "Hangzhou"} |
    +---------------------------------------------------------+
    2 rows in set (0.00 sec)

    通过update将json记录中的值进行替换

    mysql> update tab_json set data = json_remove(data,'$.age'); #通过update已经将json记录进行了修改
    Query OK, 2 rows affected (0.01 sec)
    Rows matched: 2  Changed: 2  Warnings: 0

    mysql> select * from tab_json;
    +----+--------------------------------------------------------------------------+
    | id | data                                                                     |
    +----+--------------------------------------------------------------------------+
    |  1 | {"tel": 15046464563, "passcode": "654567"}                               |
    |  2 | {"tel": 189776542, "name": "David", "olds": "12", "address": "Hangzhou"} |
    +----+--------------------------------------------------------------------------+
    2 rows in set (0.00 sec)

    备注:json_remove函数的作用就是查询时,将其中的某些key不显示,如果要更新源表,需要使用update操作.

    文档创建时间:2018年6月6日10:08:09

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  • 原文地址:https://www.cnblogs.com/chuanzhang053/p/9143644.html
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