LuoguP3701 「伪模板」主席树

题面

这个题很有意思啊。。。
其实是道最大流板子题，只连byx会赢的边，S向byx连，另一个连T。。。
注意有长者时连的边加上同方mogician的个数。。。
还要注意mogician可以无限续命，也就是他使长者+1s，自己不会-1s 那太棒了

# include <bits/stdc++.h>
# define IL inline
# define RG register
# define Fill(a, b) memset(a, b, sizeof(a))
# define Copy(a, b) memcpy(a, b, sizeof(a))
using namespace std;
typedef long long ll;
const int _(1010), __(1e6 + 10), INF(2147483647);

IL ll Read(){
    RG char c = getchar(); RG ll x = 0, z = 1;
    for(; c < '0' || c > '9'; c = getchar()) z = c == '-' ? -1 : 1;
    for(; c >= '0' && c <= '9'; c = getchar()) x = (x << 1) + (x << 3) + (c ^ 48);
    return x * z;
}

int n, m, w[6][6], lif[2][_], _1a, _1b;
int g[__], fst[_], nxt[__], to[__], cnt, S, T, lev[_], cur[_], max_flow;
queue <int> Q;
map <string, int> M;
string name[2][_];

IL void Add(RG int u, RG int v, RG int f, RG int _f){
    g[cnt] = f; to[cnt] = v; nxt[cnt] = fst[u]; fst[u] = cnt++;
    g[cnt] = _f; to[cnt] = u; nxt[cnt] = fst[v]; fst[v] = cnt++;
}

IL int Dfs(RG int u, RG int maxf){
    if(u == T) return maxf;
    RG int ret = 0;
    for(RG int &e = cur[u]; e != -1; e = nxt[e]){
        if(lev[to[e]] != lev[u] + 1 || !g[e]) continue;
        RG int f = Dfs(to[e], min(g[e], maxf - ret));
        ret += f; g[e ^ 1] += f; g[e] -= f;
        if(ret == maxf) break;
    }
    return ret;
}

IL bool Bfs(){
    Fill(lev, 0); lev[S] = 1; Q.push(S);
    while(!Q.empty()){
        RG int u = Q.front(); Q.pop();
        for(RG int e = fst[u]; e != -1; e = nxt[e]){
            if(lev[to[e]] || !g[e]) continue;
            lev[to[e]] = lev[u] + 1;
            Q.push(to[e]);
        }
    }
    return lev[T];
}

int main(RG int argc, RG char* argv[]){
	M["W"] = 1; M["HK"] = 2; M["J"] = 3; M["E"] = 4; M["YYY"] = 5;
	w[1][4] = w[1][5] = w[2][1] = w[2][4] = w[3][1] = w[3][2] = w[4][3] = w[4][5] = w[5][2] = w[5][3] = 1;
	n = Read(); m = Read(); Fill(fst, -1); T = n + n + 1;
	for(RG int i = 1; i <= n; ++i){  cin >> name[0][i]; if(M[name[0][i]] == 5) ++_1a;  }
	for(RG int i = 1; i <= n; ++i){  cin >> name[1][i]; if(M[name[1][i]] == 5) ++_1b;  }
	for(RG int i = 1; i <= n; ++i) lif[0][i] = Read();
	for(RG int i = 1; i <= n; ++i) lif[1][i] = Read();
	for(RG int i = 1; i <= n; ++i){
		RG int u1 = M[name[0][i]], u2 = M[name[1][i]];
		Add(S, i, lif[0][i] + (u1 == 3 ? _1a : 0), 0); Add(i + n, T, lif[1][i] + (u2 == 3 ? _1b : 0), 0);
		for(RG int j = 1; j <= n; ++j){
			RG int v = M[name[1][j]];
			if(!w[u1][v]) continue;
			Add(i, j + n, 1, 0);
		}
	}
	while(Bfs()) Copy(cur, fst), max_flow += Dfs(S, INF);
	printf("%d
", min(m, max_flow));
    return 0;
}