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  • 【OCP 12c】最新CUUG OCP-071考试题库(62题)

    62、(13-17)choose the best answer:

    You need to list the employees in DEPARTMENT_ID 30 in a single row, ordered by HIRE_DATE.

    Examine the sample output:

    Which query will provide the required output?

    A) SELECT LISTAGG(last_name, '; ') "Emp_list", MIN(hire_date) "Earliest"

    FROM employees

    WHERE department_id = 30

    WITHIN GROUP ORDER BY hire_date;

    B) SELECT LISTAGG(last_name, '; ') "EMP_LIST", MIN(hire_date) "Earliest"

    FROM employees

    WHERE department_id = 30

    ORDER BY hire_date;

    C) SELECT LISTAGG(last_name, '; ')

    WITHIN GROUP (ORDER BY hire_date) "Emp_list", MIN(hire_date) "Earliest"

    FROM employees

    WHERE department_id = 30;

    D) SELECT LISTAGG(last_name)

    WITHIN GROUP ORDER BY (hire_date) "Emp_list", MIN(hire_date) "Earliest"

    FROM employees

    WHERE department_id = 30;

    Answer:C

    (解析:工作中会用到把查出来的列的值去重合并成一行显示,可以使用 listagg() WITHIN GROUP () 将

    多行合并成一行:

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  • 原文地址:https://www.cnblogs.com/cnblogs5359/p/10481761.html
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