zoukankan      html  css  js  c++  java
  • 2017 ACM/ICPC 沈阳 K题 Rabbits

    Here N (N ≥ 3) rabbits are playing by the river. They are playing on a number line, each occupying a different integer. In a single move, one of the outer rabbits jumps into a space between any other two. At no point may two rabbits occupy the same position. 
    Help them play as long as possible

    InputThe input has several test cases. The first line of input contains an integer t (1 ≤ t ≤ 500) indicating the number of test cases. 
    For each case the first line contains the integer N (3 ≤ N ≤ 500) described as above. The second line contains n integers a1a1 < a2a2 < a3a3 < ... < aNaN which are the initial positions of the rabbits. For each rabbit, its initial position 
    aiai satisfies 1 ≤ aiai ≤ 10000. 
    OutputFor each case, output the largest number of moves the rabbits can make. 
    Sample Input

    5
    3
    3 4 6
    3
    2 3 5
    3
    3 5 9
    4
    1 2 3 4
    4
    1 2 4 5

    Sample Output

    1
    1
    3
    0
    1
    签到题:Orz
     1 #include<bits/stdc++.h>
     2 using namespace std;
     3 int T,num[510],sum[510];
     4 int main()
     5 {
     6     scanf("%d",&T);
     7     while(T--)
     8     {
     9         int n;
    10         scanf("%d",&n);
    11         int len=0;
    12         for(int i=1;i<=n;i++) scanf("%d",&num[i]);
    13         for(int i=1;i<n;i++) sum[i]=num[i+1]-num[i]-1,len+=sum[i];
    14         int ans=len-min(sum[1],sum[n-1]);
    15         printf("%d
    ",ans);
    16     }
    17     return 0;
    18 }
    View Code

      

  • 相关阅读:
    smdkv210
    wireshark常用过滤规则
    go json序列化不填充默认值
    refactoring.guru-重构-如何重构
    refactoring.guru--重构--何时重构
    refactoring.guru--重构--技术债务
    refactoring.guru学习记录--重构--整洁的代码
    window7下python3 编译pjsua
    go 单元测试框架介绍
    算法图解学习笔记之算法
  • 原文地址:https://www.cnblogs.com/csushl/p/9784969.html
Copyright © 2011-2022 走看看