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  • Ordinal Numbers(简单)

    Ordinal Numbers

    Time Limit: 2 Seconds      Memory Limit: 65536 KB

    Ordinal numbers refer to a position in a series. Common ordinals include zeroth, first, second, third, fourth and so on. Ordinals are not often written in words, they are written using digits and letters. An ordinal indicator is a sign adjacent to a numeral denoting that it is an ordinal number, rather than a cardinal number. In English, the suffixes -st (e.g. 21st), -nd (e.g. 22nd), -rd (e.g. 23rd), and -th (e.g. 24th) are used. The rules are as follows:

    • If the tens digit of a number is 1, then write "th" after the number. For example: 13th, 19th, 112th, 9311th.
    • If the tens digit is not equal to 1, then use "st" if the units digit is 1, "nd" if the units digit is 2, "rd" if the units digit is 3, and "th" otherwise: For example: 2nd, 7th, 20th, 23rd, 52nd, 135th, 301st.

    Input

    There are multiple test cases. The first line of input is an integer T ≈ 1000 indicating the number of test cases.

    Each test case consists of a cardinal number 0 ≤ n < 1,000,000,000.

    Output

    For each test case, output the corresponding ordinal number.

    Sample Input

    5
    1
    2
    3
    4
    1024
    

    Sample Output

    1st
    2nd
    3rd
    4th
    1024th
    

    References

     1 #include <iostream>
     2 #include <string>
     3 #include <cstdio>
     4 #include <cmath>
     5 #include <cstring>
     6 #include <algorithm>
     7 #include <map>
     8 #include <vector>
     9 #include <set>
    10 #include <queue>
    11 #include <stack>
    12 #define LL long long
    13 #define MAXI 2147483647
    14 #define MAXL 9223372036854775807
    15 #define eps (1e-8)
    16 #define dg(i) cout << "*" << i << endl;
    17   
    18 using namespace std;
    19   
    20 int main()
    21 {
    22     int t, n, m;
    23     scanf("%d", &t);
    24     while(t--)
    25     {
    26         scanf("%d", &n);
    27         if((n / 10) % 10 == 1) printf("%dth\n", n);
    28         else
    29         {
    30             m = n % 10;  //获得最后一位数字
    31             printf("%d", n);
    32             if(m == 1) puts("st");
    33             else if(m == 2) puts("nd");
    34             else if(m == 3) puts("rd");
    35             else puts("th");
    36         }
    37     }
    38     return 0;
    39 }
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  • 原文地址:https://www.cnblogs.com/cszlg/p/2932442.html
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