关于int8_t,uint8_t.....等数据类型的理解

实习中，今天在看公司源码的时候，发现前辈给的代码都是这样的

typedef int8_t int8;
typedef uint8_t uint8;
typedef int16_t int16;
typedef uint16_t uint16;
typedef word_t word16;
typedef int32_t int32;
typedef uint32_t uint32;
typedef dword_t dword32;
typedef int64_t int64;
typedef uint64_t uint64;
typedef uint32 color_t;

typedef time_t time64;
typedef wchar_t char16;//宽字符
typedef char    char8;

　身为小白的我内心是这样的      ？？？？？？？

查找后得出了结论，其实这些都是已经被typedef过的类型：

typedef signed char int8_t;
typedef unsigned char uint8_t;

typedef int int16_t;
typedef unsigned int uint16_t;

typedef long int32_t;
typedef unsigned long uint32_t;

typedef long long int64_t;
typedef unsigned long long uint64_t;   

　　这些包含在inttypes.h头文件，据说这样做的原因是方便移植，比如int8就是8位大小占一字节，int32，，32位大小4字节… 
这样相对应的占位符也就清楚了：

char /unsigned char: %c
int : %d 
unsigned int: %u  
long: %ld; 
unsigned long:%lu
long long: %lld(%l64d)
unsigned long long:%Ilu(%l64u)

　即：

int8_t:%c;
uint8_t:%c;

int16_t: %d;
uint16_t:%u;

int32_t:%ld;
uint32_t:%lu;

int64_t：%lld(%l64d);
uint64_t:%llu(%l64u);

资料：https://blog.csdn.net/eusia/article/details/76401235